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kobusy [5.1K]
3 years ago
7

Write a balanced equation for the combination reaction described, using the smallest possible integer coefficients.

Chemistry
2 answers:
Masja [62]3 years ago
6 0

Answer:

H2(g) + I2(g) → 2HI(g)

Explanation:

Step 1: Data given

hydrogen gas = H2(g)

iodine gas = I2(g)

hydrogen iodide = HI(g)

Step 2: The unbalanced equation

H2(g) + I2(g) → HI(g)

Step 3: Balancing the equation

On theleft side we have 2x H (in H2), On the right side we have 1x H (in HI)

To balance the amount of H on both sides we have to multiply HI on the right by 2

By multiplying HI by 2, the amount of O on both sides is also equal. The equation is balanced.

H2(g) + I2(g) → 2HI(g)

Kazeer [188]3 years ago
4 0

Answer:

H2 + I2 —> 2HI

Explanation:

H2 + I2 —> HI

Now, let us balance the equation. This can be achieved by doing the following:

There are 2 atoms of H on the left side of the equation and 1atom on the right side. It can be balance by putting 2 in front of HI as shown below:

H2 + I2 —> 2HI

Now the equation is balanced as there are equal numbers of atoms of the different elements present on both sides of the equation.

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Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin f
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Answer:

15.0 µm

Step-by-step explanation:

Density = mass/volume

        D = m/V     Multiply each side by V

      DV = m        Divide each side by D

        V = m/D

Data:

m = 1.091 g

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 l = 10.0 cm

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Calculation:

<em>(a) Volume of foil </em>

V = 1.091 g  × (1 cm³/7.28 g)

  = 0.1499 cm³

(b) <em>Thickness of foil </em>

The foil is a rectangular solid.

V  = lwh                            Divide each side by lw

h = V/(lw)

   = 0.1499/(10 × 10)

   = 1.50 × 10⁻³ cm           Convert to millimetres

   = 0.015 mm                  Convert to micrometres

   = 15.0 µm

The foil is 15.0 µm thick.

4 0
3 years ago
How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significa
satela [25.4K]
The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
                                                                           = 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g

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