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3 years ago

Why would a robot process something faster than a human

2 answers:

8 0

A robot is a machine. It is often, or almost always, automatic, which means that it is able to perform activities on its own without the aid of external variables, like humans. It moves in the way that it was originally programmed, or designed to act. These actions are described as 'intents' of its own.

True [87]3 years ago

6 0

Answer:

A robot is most of the time a lot more useful.

Explanation:

;)

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water at 20c discharges from a stroke tank through a 150m length of horizontal pipe. The pipe is smooth and has a diameter of 75

inessss [21]

Answer:

The dept of the water needed is 26.11m

Explanation:

Given the following parameters:

Length of the pipe = $150m$

Diameter of the pipe = $75mm = 0.75m$

Volumetric flow rate $1m^{3}/s$

Knowing that:

Volumetric flowrate $= area (A) * Velocity(V)$

==> $0.1 = A*V$ *Knowing that $V = \sqrt{2gh}$

==> $0.1 = \frac{\pi }{4}* (0.075)^{2} * \sqrt{2gh}$

==> $h = 26.11m$

Hence, the dept of water needed to produce a volumetric flow rate of $1m^{3}/s$ is 26.11m.

7 0

3 years ago

Thread cancellation is : Group of answer choices c) the task of terminating a thread before it has completed a) the task of dest

Mariana [72]

Answer:

Thread cancellation is the task of terminating a thread before it has completed.

Explanation:

In computers and technology, the concept of thread cancellation explains how a thread can be stopped while it is still in the process of execution.

It can also be done in such a way that it checks at intervals if it can safely cancel itself before it then proceeds with the cancellation.

3 0

3 years ago

The area under the moment diagram is shear force. a)-True b)-False

liberstina [14]

Answer:

False

Explanation:

as we know that $V(x)=\frac{dM}{dx}\\ \\=> M(x) = \int\limits^x_o {V(x)} \, dx \\\\$

=> Area under shear diagram gives the moment at any point but the reverse cannot be established from the same relation

8 0

3 years ago

The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel. Determine the magnitude of forc

Sonbull [250]

Answer:

Magnitude of force P = 25715.1517 N

Explanation:

Given - The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel.

To find - Determine the magnitude of force P so that the rigid beam tilts 0.015∘.

Proof -

Given that,

Diameter = 12 mm = 0.012 m

Length = 0.6 m

$\theta$ = 0.015°

Youngs modulus of elasticity of 34 stainless steel is 193 GPa

Now,

By applying the conditions of equilibrium, we have

∑fₓ = 0, ∑ $f_{y}$ = 0, ∑M = 0

If ∑ $M_{A}$ = 0

⇒ $F_{BC}$ ×0.9 - P × 0.6 = 0

⇒ $F_{BC}$ ×3 - P × 2 = 0

⇒ $F_{BC}$ = $\frac{2P}{3}$

If ∑ $M_{B}$ = 0

⇒ $F_{AD}$ ×0.9 = P × 0.3

⇒ $F_{AD}$ ×3 = P

⇒ $F_{AD}$ = $\frac{P}{3}$

Now,

Area, A = $\frac{\pi }{4} X (0.012)^{2}$ = 1.3097 × 10⁻⁴ m²

We know that,

Change in Length , $\delta$ = $\frac{P l}{A E}$

Now,

$\delta_{AD} = \frac{P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9} }$ = 9.1626 × 10⁻⁹ P

$\delta_{BC} = \frac{2P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9} }$ = 1.83253 × 10⁻⁸ P

Given that,

$\theta$ = 0.015°

⇒ $\theta$ = 2.618 × 10⁻⁴ rad

So,

$\theta = \frac{\delta_{BC} - \delta_{AD}}{0.9}$

⇒2.618 × 10⁻⁴ = ( 1.83253 × 10⁻⁸ P - 9.1626 × 10⁻⁹ P) / 0.9

⇒P = 25715.1517 N

∴ we get

Magnitude of force P = 25715.1517 N

6 0

3 years ago

The outer surface of a spacecraft in space has an emissivity of 0.6 and an absorptivity of 0.2 for solar radiation. If solar rad

Korolek [52]

Answer:

$T_{surf} =$ 3.9°C

Explanation:

solution:

we express the surface temperature from the quality of the emitted and absorbed heat rates:

$Q_{abs} =Q_{em} \\\$

$\alpha Q_{inc}=$ εσA $T^{4} _{surf}$

$T_{surf} =$ $\sqrt[4]{}$ $\alpha$ /εσ* $\frac{Q_{inc} }{A}$ ........................(1)

where

$\alpha$ =0.2

ε=0.6

A=5.67*10^-8 W/m^2K^4

$Q_{inc}$ = 1000 W/m^2

now putting these value in eq 1

$T_{surf} =$ 3.9°C

6 0

3 years ago