Properties.....................
Answer:
a)567mg
b)0.567 grams
Explanation:
There are 7 days in a week, so we multiply the number of weeks by the number of daily dosage.
81mg*7=567mg
1 gram is 1000 mg
we divide 567 by 1000 to get the value in grams
Answer:
The concentration of the newly prepared solution is 8 * 10^-5 M
Explanation:
The most common way to solve this problem is to use the following formula
c1*V1 = c2*V2
with c1 = 1 * 10^-3 M
with V1 = 20 mL = 0.02 L
with c2 = TO BE DETERMINED
with V2 = 250 mL = O.250 L
10^-3 * 0.02 L = c2 * 0.250L
0.00002 = c2 * 0.250L
c2 = 0.00002 / 0.250 L
c2 = 0.00008 M = 8 * 10^-5 M
The concentration of the newly prepared solution is 8 * 10^-5 M
The atomic masses written for every element in the periodic table is the average atomic weight that is calculated from the element's isotopes. The formula would be:
Average Atomic Weight = ∑(Isotope Mass×Relative Abundance)
Substituting the values:
Average Atomic Weight = (331 amu×0.35) + (337 amu×0.65)
Average Atomic Weight = 334.9 amu
The mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.
<h3>How to calculate mass of an element in a compound?</h3>
According to this question, a 10.4 g sample of CaSO4 is found to contain 3.06 g of Ca and 4.89 g of O.
This means that the mass of sulfur in the 10.4g of CaSO4 is 10.4g - (3.06g + 4.89g) = 10.4g - 7.95g = 2.45g
Next, we calculate the percent ratio of each element in the compound; CaSO4.
- Ca = 3.06g/10.4g × 100 = 29.42%
- S = 2.45g/10.4g × 100 = 23.56%
- O = 4.89g/10.4g × 100 = 47.02%
According to this question, a sample of CaSO4 with a mass of 65.8 g is given. The mass of each element in this compound is as follows:
- Ca = 29.42/100 × 65.8g = 19.36g
- S = 23.56/100 × 65.8g = 15.50g
- O = 47.02/100 × 65.8g = 30.94g
Therefore, the mass of sulfur in a sample of CaSO4 with a mass of 65.8 g is 15.50g.
Learn more about mass at: brainly.com/question/13672279
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