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mars1129 [50]
3 years ago
5

You are comparing distillation column designs at 1 atm and 3 atm total pressure for a particular separation. You have the same f

eed in both cases, and the feed is a saturated liquid in both cases. The product specifications do not change, and the same reflux ratio is used in both cases.
Compared to the design at 3 atm, the design at 1 atm will have: (Select one)a) more stages, fewer stages, the same number of stagesb) a larger diameter, a smaller diameter, the same diameterc) a higher reboiler temperature, a lower reboiler temp, the same reboiler temp
Engineering
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

more number of stages will be required , a smaller diameter , a higher reboiler temperature

Explanation:

It is stated in the question that the product specifications and the reflux ratio do not change.

The pressure in a distillation column varies:

  • directly as the diameter of the distillation column
  • inversely as the number of stages required for the design
  • inversely as the temperature of the reboiler

Based on the theory stated above, the distillation column design at a pressure of 1 atm requires a more number of stages than the design with 3 atm, it has a smaller diameter than the design at 3 atm. It also has a higher reboiler temperature than the design with 3 atm.

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A heat engine that receives heat from a furnace at 1200°C and rejects waste heat to a river at 20°C has a thermal efficiency of
viktelen [127]

Answer:

second-law efficiency  = 62.42 %

Explanation:

given data

temperature T1 = 1200°C = 1473 K

temperature T2 = 20°C  =  293 K

thermal efficiency η = 50 percent

solution

as we know that thermal efficiency of reversible heat engine between same  temp reservoir

so here

efficiency ( reversible ) η1 = 1 - \frac{T2}{T1}      ............1

efficiency ( reversible ) η1  = 1 - \frac{293}{1473}  

so efficiency ( reversible ) η1  = 0.801

so here second-law efficiency of this power plant is

second-law efficiency = \frac{thernal\ efficiency}{0.801}

second-law efficiency = \frac{50}{0.801}  

second-law efficiency  = 62.42 %

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What type of companies would employ in mechanics engineering​
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What is the average linear (seepage) velocity of water in an aquifer with a hydraulic conductivity of 6.9 x 10-4 m/s and porosit
jeka94

Answer:

a. 0.28

Explanation:

Given that

porosity =30%

hydraulic gradient = 0.0014

hydraulic conductivity = 6.9 x 10⁻4 m/s

We know that average linear velocity given as

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v=\dfrac{6.9\times 10^{-4}}{0.3}\times0.0014\ m/s

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The velocity in m/d      ( 1 m/s =86400 m/d)

v= 0.27 m/d

So the nearest answer is 'a'.

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Air at T1 = 32°C, p1 = 1 bar, 50% relative humidity enters an insulated chamber operating at steady state with a mass flow rate
RUDIKE [14]

Answer:

4.5kg/min

Explanation:

Given parameters

T_1 = 32^0 C,  m_1 = 3 kg/min, T_2 = 7^0 C ,T_3 = 17^0

if we take  

The mass flow rate of the second stream = m_2(kg/min)

The mass flow rate of mixed exit stream = m_3 (kg/min)

Now from mass conservation

m_3 = m_2 + m_1

m_3 = m_2 + 3 (kg/min)

The temperature of the mixed exit stream given as

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Therefore the mass flow rate of second stream will be 4.5 kg/min.

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