You have 15g of sodium iodide (Nal), which has a molecular weight of 150 g/mol. You place it all in a beaker and fill the beaker
2 answers:
Answer:
A. 0.1M .
Explanation:
Hello,
In this case, we first compute the moles of sodium iodide by using its molar mass:
Then, since the volume of the solution is 1 litre, we can easily compute the molarity:
Hence, answer is A. 0.1M
Best regards.
Answer:
A. 0.1 M
Explanation:
Given data
- Mass of NaI (solute): 15 g
- Molar mass of NaI: 150 g/mol
- Volume of solution: 1 L
Step 1: Calculate the moles of solute
Step 2: Calculate the molarity of the solution
The molarity of the solution is equal to the moles of solute divided by the liters of solution.
The solution is 0.1 M.
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Answer:
Two moles.
Explanation:
Sulphuric (sulfuric) acid is a diprotic acid. When one mole of
molecules dissolve in water, two moles of
ions would be produced.
.
On the other hand, sodium hydroxide is a monoprotic base. When one mole of
formula units dissolve in water, only one mole of hydroxide ions
would be produced.
.
Note that and
react at a one-to-one ratio:
.
As a result, it would take of
to react with the
of
that was released when
of
is dissolved in water. Since one mole of
formula units could produce only one mole of
, it would take
of
formula units to produce that
of
for reacting with
of
.