Question

You have 15g of sodium iodide (Nal), which has a molecular weight of 150 g/mol. You place it all in a beaker and fill the beaker to until you have one liter of solution. What is the molarity of the solution?
A. 0.1M

B. 15M

C. 0.15M

D. 0.01M

Answer 1

Answer:

A. 0.1M .

Explanation:

Hello,

In this case, we first compute the moles of sodium iodide by using its molar mass:

$n=15g*\frac{1mol}{150g}=0.1mol$

Then, since the volume of the solution is 1 litre, we can easily compute the molarity:

$M=\frac{n}{V}=\frac{0.1mol}{1L} \\\\M=0.1M$

Hence, answer is A. 0.1M

Best regards.

Answer 2

Answer:

A. 0.1 M

Explanation:

Given data

• Mass of NaI (solute): 15 g

• Molar mass of NaI: 150 g/mol

• Volume of solution: 1 L

Step 1: Calculate the moles of solute

$15g \times \frac{1mol}{150g} = 0.10mol$

Step 2: Calculate the molarity of the solution

The molarity of the solution is equal to the moles of solute divided by the liters of solution.

$M = \frac{0.10mol}{1L} =0.1M$

The solution is 0.1 M.