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Mazyrski [523]
2 years ago
8

Define the following terms a. crystallization b. radical c. mixture​

Chemistry
2 answers:
anastassius [24]2 years ago
8 0

a) Crystallization :- Crystallization is a chemical process in which the solid-liquid separation technique occurs. This process causes mass transfer of a solute from the liquid solution to a pure solid crystalline phase.

b) Radical :- A radical is an atom of an element or a group of atoms of different elements that behaves as a single unit with a positive or negative charge on it.

c) Mixture :- A mixture is a combination of two or more substances (elements or compounds) which is not done chemically.

Explanation:

<h3>Hope it helps you!! </h3>
Brut [27]2 years ago
4 0

Answer:

(a) Crystallization is a process which helps to separate a pure solid from a solution in its crystal form. This is the in use to purify solid. For an example the salt we get from seawater can have many impurities in it. Hence, the process of crystallization is in use to remove these impurities.

(b) A radical is an atom of an element or a group of atoms of different elements that behaves as a single unit with a positive or negative charge on it.

(c) Mixtures are constituted by more than 1 kind of pure form known as substance. There are 2 types of mixture:-

(i) homogeneous

A mixture in which the constituents are uniformly distributed throughout without any clear boundary of separation

(ii) Heterogeneous

A mixture in which constituents don't have uniform composition and has a visible boundary of separation.

Explanation:

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Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

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3 years ago
Molar mass in sulfuric acid
EleoNora [17]

Hey there!

Sulfuric acid: H₂SO₄

H: 2 x 1.008 = 2.016

S: 1 x 32.065 = 32.065

O: 4 x 16 = 64

--------------------------------

                 98.081 g/mol

The molar mass of sulfuric acid is 98.081 g/mol.

Hope this helps!

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