Answer:
Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.
Answer:
a. 156.41m
b. directly over the target
Explanation:
a) At the point of release, the weight will have:
Horizontal:
velocity of 40m/s (same as the plane)
Acceleration of zero since it is not under the influence of any force.
Vertical:
initial Velocity - zero at this instant
Acceleration - Towards the ground with g (9.81m/s^2)
from newton's equation of motion, since its falling under gravity, the horizontal component wont be involved
s = ut + (1/2)at^2
u = initial velocity
a = acceleration
s = displacement
t = time taken
75 = 0 + (1/2)(9.81)t^2
t^2=15.29
t=3.91
t = 3.91s
Applying the time of flight to the horizontal components:
Distance = speed x time
= 40 x 3.91
= 156.41m
B) The pilot looks down at the weight after she drops it. Where is the plane located at the instant the weight hits the ground?
not yet over the target
past the target
directly over the target
not enough information to determine
c. directly over the target. will be the correct answer
The answer is Computer game.
Scientific modelling is an experimental enterprise, the purpose of that is to make a distinct section or piece of the universe accessible to recognize, describe, quantify, imagine, or invent by connecting it to existing and customarily ordinarily allowed information.
Answer:
A. P = 18.75 watts
B. P = 75 watts
Explanation:
V = 120 Volts
P = VI
I = P/V = 75/120 = 0.625 Amps
V = IR
R = V/I
R = 120/0.625 = 192 Ω
So the resistance of the bulb is 192 Ω and it does not change as it is given in the question.
A. How much power is dissipated in a light bulb that is normally rated at 75 W, if instead we hook it up to a potential difference of 60 V?
As P = VI and I = V/R
P = V*(V/R)
P = V²/R
P = (60)/192
P = 18.75 watts
As expected, it will dissipate less power (18.75 watts) than rated power due to not having rated voltage of 120 Volts.
I = V/R = 60/192 = 0.3125 Amps
or I = P/V = 18.75/60 = 0.3125 Amps
Since the resistance is being held constant, decreasing voltage will also decrease current as V = IR voltage is directly proportional to the current.
B. How much power is dissipated in a light bulb that is normally rated at 75 W, if instead we hook it up to a potential difference of 120 V?
P = V*(V/R)
P = V²/R
P = 120/192 = 75 watts
I = P/V = 75/120 = 0.625 Amps
As expected, it will dissipate rated power of 75 watts at rated voltage of 120 Volts.
1 angstrom = 10^-8 cm
6.5 x 10-4 cm = 65 000 x 10-8 cm = 65 000 angstroms
answer 65 000 angstroms