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3 years ago

Identify a pattern taht you can observe in the graph

Physics

1 answer:

bazaltina [42]3 years ago

8 0

One pattern is the distance between two points

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Which of the following is an example of speed?

Arturiano [62]

The cat has a speed. The truck and the bicycle both have velocity. We can't be sure of what the plane has.

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3 years ago

A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The ang

olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: $s_c = \omega_ct = 0.233t$

For the horse: $s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2$

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

$s_c = s_h$

$0.233t = 1.57 + 0.0068t^2$

$0.0068t^2 - 0.233t + 1.57 = 0$

$t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$t= \frac{0.233\pm \sqrt{(-0.233)^2 - 4*(0.0068)*(1.57)}}{2*(0.0068)}$

$t= \frac{0.233\pm0.11}{0.0136}$

t = 25.05 or t = 9.22

Since we are looking for the shortest time we will pick t = 9.22 s

6 0

4 years ago

A motor cycle travelling at 10 m/s accelerates at 4m/s(squared) for 8s.

Sever21 [200]

10 x 4^2 = 160 / 8..

V = 20m/s...

...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.

This is my guess since the problem says 4m/s^2

V= distance/ ST (traveled/used)

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3 years ago

An object that is farther from a converging lens than its focal point always has an image that is _____.

bearhunter [10]

Smaller in size (Pt. Sized)

5 0

3 years ago

Mathphys this is the last time i ever ask for help PLEASEHELP ME

Ivenika [448]

Explanation:

Heat flow = conductivity × area × change in temperature / thickness

q' = kAΔT/t

13.3 W = k (1.56 m²) (7.8°C) / (0.0234 m)

k = 0.0256 W/m/°C

Heat lost by water = heat gained by ice

-mCΔT = mL + mCΔT

-(1000 g) (1 cal/g/°C) (12°C − 37°C) = m (79.7 cal/g) + m (1 cal/g/°C) (12°C − 0°C)

25,000 cal = (91.7 cal/g) m

m = 272.6 g

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3 years ago