Question

Mathphys this is the last time i ever ask for help PLEASEHELP ME

Answer 1

Explanation:

Heat flow = conductivity × area × change in temperature / thickness

q' = kAΔT/t

13.3 W = k (1.56 m²) (7.8°C) / (0.0234 m)

k = 0.0256 W/m/°C

Heat lost by water = heat gained by ice

-mCΔT = mL + mCΔT

-(1000 g) (1 cal/g/°C) (12°C − 37°C) = m (79.7 cal/g) + m (1 cal/g/°C) (12°C − 0°C)

25,000 cal = (91.7 cal/g) m

m = 272.6 g