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Zigmanuir [339]
3 years ago
12

Mathphys this is the last time i ever ask for help PLEASEHELP ME

Physics
1 answer:
Ivenika [448]3 years ago
8 0

Explanation:

Heat flow = conductivity × area × change in temperature / thickness

q' = kAΔT/t

13.3 W = k (1.56 m²) (7.8°C) / (0.0234 m)

k = 0.0256 W/m/°C

Heat lost by water = heat gained by ice

-mCΔT = mL + mCΔT

-(1000 g) (1 cal/g/°C) (12°C − 37°C) = m (79.7 cal/g) + m (1 cal/g/°C) (12°C − 0°C)

25,000 cal = (91.7 cal/g) m

m = 272.6 g

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Answer:

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any force where you push or pull is always applied force.

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3 years ago
A ball is thrown at an angle of 45° to the ground. if the ball lands 87 m away, what was the initial speed of the ball? (round
Troyanec [42]
Just try your best best friend everyone
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A vector d has a magnitude of2.6 m and points north. What are the magnitudes and directions of the vectors (a) - d, (b) d/2.0, (
AleksandrR [38]

Solution :

A vector is defined as an element that has magnitude of some measure and direction.

It is given there is vector 'd' which has magnitude 2.6 m and its direction is towards north.

a). -d

    The magnitude of the vector '-d' is 2.6 m and its direction is reversed, i.e. its direction is towards south.

b). d/2.0

  The magnitude of the vector 'd/2.0' is 1.3 m and its direction is towards north.

c). - 2.5d

  The magnitude of the vector increases by 2.5 times i.e. 2.5 x 2.6 = 6.5 m and the direction is towards south.

d). 5.0d

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4 0
3 years ago
Which fundamental force is very strong across a short distance?
lesya692 [45]

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5 0
3 years ago
Read 2 more answers
A satellite is in circular orbit around the earth. The orbit the satellite is at a height of 420 km above the earth's surface. F
astraxan [27]

Answer:

7661.06 m/s

Explanation:

R = Radius of Earth = 6.38\times 10^6\ m

h = Distance from the Earth = 420000 m

G = Gravitational constant = 6.674\times 10^{-11} N m^2/kg^2

M = Mass of Earth = 5.98\times 10^{24}\ kg

V=\sqrt{g{\frac{R^2}{R + h}}}\\\Rightarrow V=\sqrt{\frac{GM}{R^2}{\frac{R^2}{R + h}}}\\\Rightarrow V=\sqrt{\frac{6.674\times 10^{-11}\times 5.98\times 10^{24}}{(6.38\times 10^6)^2}{\frac{(6.38\times 10^6)^2}{6.38\times 10^6 + 420000}}}\\\Rightarrow V=7661.06\ m/s

The orbital speed of the satellite is 7661.06 m/s

6 0
4 years ago
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