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Anna007 [38]
3 years ago
6

For a single substance at atmosphericpressure, classify the following as describing a spontaneousprocess, a nonspontaneous proce

ss, or an equilibrium system.1. Solid melting above its melting point2.liquid freezing below its freezing point3. gas condensing above its condensation point4. liquid vaporizing below its boiling point5. solid melting below its melting point6. solid and liquid together at the melting point with no netfreezing or melting7. gas condensing below its condensation point8. liquid and gas together at the boiling point with no netcondensation or vaporization9. liquid freezing above its freezing point10. liquid vaporizing above its boiling point
Chemistry
1 answer:
Archy [21]3 years ago
7 0

IDK IDK IDK IDK IDK IDK

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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
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Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

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