Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
Explanation :
First we have to calculate the heat released by the combustion.
where,
q = heat released = ?
= specific heat of calorimeter = 
= change in temperature = 
Now put all the given values in the above formula, we get:
Thus, the heat released by the combustion = 70.43 kJ
Now we have to calculate the molar enthalpy combustion.
where,
= molar enthalpy combustion = ?
q = heat released = 70.43 kJ
n = number of moles cymene = 
Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
Answer:
E. 8.08 x 10⁴.
Explanation:
Hello,
In this case, for the reaction:
We can compute the Gibbs free energy of reaction via:
Since both the entropy and enthalpy of reaction are given at 298 K (standard temperature), therefore:
Then, as the equilibrium constant is computed as:
We obtain:
For which the answer is E. 8.08 x 10⁴.
Best regards,
Answer:
41.4 g
Explanation:
2Na(s) + 2H2O (l) ----> 2NaOH ( aq) + H2 (g)
According to the above balnced chemical equation the ratio between moles of H2 gas formed to moles of Na used up is 1:2
Molar mass ( Mass of 1 mol) Of H2 gas is 2 gmol-1
So in 1.8 g of H2 0.9 mol should be present
Therefore no. of moles of Na used should be 2× 0.9 = 1.8 moles
Molar mass of Na= 23 gmol-1
So mass of 1.8 mol of Na = 1.8× 23 g = 41.4g
That's actually a polyatomic Ion, so it's an Ionic bond, because Aluminum is a metal, and sulfate is a covalent compound.
