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Sergeu [11.5K]
3 years ago
8

1. In the models, what particles do the colored and plain sesame seeds represent? What particles do the poppy seeds represent

Chemistry
2 answers:
Veronika [31]3 years ago
6 0
Ok the answers to the hole .doc is 
1. Neutrons, Protons, and Electrons
2. N<span>ucleus
3. N</span>eutrons and Protons
4. Electrons
5. Because they represent different things (I would put this in your own words)
enyata [817]3 years ago
4 0
<h2>Answer 1) : The colored and plain sesame seeds represent the subatomic particles neutrons and protons. </h2><h3>Explanation :</h3>

The attached model of the atom has subatomic particles as neutrons and protons; which are present in the center of the nucleus of the atom. Where neutrons are neutrally charged particles in the nucleus and protons are positively charged particles present in the nucleus of the atom.

<h2>Answer 2) The poppy seeds represent the electrons.</h2><h3>Explanation :</h3>

The poppy seeds used in this atomic model represents the revolving electrons around the the nucleus of the atom in orbits. These are negatively charges subatomic particles which revolves around the nucleus.

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A buffer is composed of nh3 and nh4cl. How would this buffer solution control the ph of a solution when a small amount of a stro
Shkiper50 [21]

Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)

So, OH^{-} is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of OH^{-} increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant.

Therefore excess amount of OH^{-} combines with NH_{4}^{+} to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

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3 years ago
Which of the following is formed by intense heat and pressure over millions of years?
kumpel [21]

Answer:

B:Metamorphic

Explanation:

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Circle the solution with the highest concentration
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5 0
2 years ago
Read 2 more answers
20.00 g of aluminum (al) reacts with 78.78 grams of molecular chlorine (cl2) all of each reactant is completely consumed and a s
marysya [2.9K]

The mass of the product is <em>98.78 g.</em>

The word equation is

aluminum + chlorine → product

20.00 g + 98.78 g → <em>x</em> g

If each reactant is completely consumed, the <em>Law of conservation of Mass </em>tells us the mass of the product must be 98.78 g.

8 0
3 years ago
In Lab 10 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 5.00 ml o
Zigmanuir [339]

Answer:

Stock  solution =  1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

<u>Step 1:</u> Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

<u>Step 2</u>: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

<u>Step 3:</u> Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

<u>Step 4</u>: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

<u>Step 5:</u> Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

<u>Step 6</u>: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

5 0
3 years ago
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