1. In the models, what particles do the colored and plain sesame seeds represent? What particles do the poppy seeds represent

Chemistry

2 answers:

Veronika [31]4 years ago

6 0

Ok the answers to the hole .doc is
1. Neutrons, Protons, and Electrons
2. N<span>ucleus
3. N</span>eutrons and Protons
4. Electrons
5. Because they represent different things (I would put this in your own words)

enyata [817]4 years ago

4 0

<h2>Answer 1) : The colored and plain sesame seeds represent the subatomic particles neutrons and protons. </h2><h3>Explanation :</h3>

The attached model of the atom has subatomic particles as neutrons and protons; which are present in the center of the nucleus of the atom. Where neutrons are neutrally charged particles in the nucleus and protons are positively charged particles present in the nucleus of the atom.

<h2>Answer 2) The poppy seeds represent the electrons.</h2><h3>Explanation :</h3>

The poppy seeds used in this atomic model represents the revolving electrons around the the nucleus of the atom in orbits. These are negatively charges subatomic particles which revolves around the nucleus.

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Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)

cupoosta [38]

Answer:

$m_{CaCO_3}=0.179gCaCO_3$

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

$PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2$

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

$m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3$