Question

Perhatikan persamaan termokimia berikut.

Answer 1

the reaction is

HCl (aq) + NaOH (aq) -> NaCl (aq) + H2O (l).

the enthalpy of reaction is H=-54 kJ

Which means that one mole of HCl reacts with one mole of NaOH and gives 54 kJ of energy / heat

The reaction is exothermic and the graph will be like as shown in figure (1)

The question is

What is the enthalpy change if 10 mL HCl 1 M is reacted with 20 mL 1 M NaOH?

Moles of HCl  = molarity X volume = 1 M X 10 mL = 10 mmoles

moles of NaOH reacted = moles of NaOH

so total moles of acid base reacted = 10mmoles = water formed

when one mole of acid base reacted to give one mole of H2O

so when 10mmole of water are formed energy released is = 54 X 10 X 10^-3 = 0.54 kJ

reaksinya

HCl (aq) + NaOH (aq) -> NaCl (aq) + H2O (l).

entalpi reaksi adalah H = -54 kJ

Yang berarti satu mol HCl bereaksi dengan satu mol NaOH dan memberikan 54 kJ energi / panas

Reaksinya eksotermik dan grafiknya akan seperti yang ditunjukkan pada gambar (1)

Pertanyaannya adalah

Apa perubahan entalpi jika 10 mL HCl 1 M direaksikan dengan 20 mL 1 M NaOH?

Moles HCl = molaritas X volume = 1 M X 10 mL = 10 mmoles

Tahi lalat NaOH bereaksi = mol NaOH

sehingga jumlah mol asam basa bereaksi = 10mmol = air terbentuk

ketika satu mol asam basa bereaksi untuk memberikan satu mol H2O

jadi ketika 10mmole air terbentuk, energi yang dilepaskan adalah = 54 X 10 X 10 ^ -3 = 0,54 kJ