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dimaraw [331]
3 years ago
15

If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angula

r velocity of the pulley 1.5s later?
Physics
1 answer:
snow_lady [41]3 years ago
6 0

Here we know that

\omega_i = - 8.4 rad/s

\alpha = - 2.8 rad/s^2

t = 1.5 s

now from kinematics we have

\omega_f = \omega_i + \alpha t

now from above all values we have

\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)

\omega_f = -8.4 + (-4.2)

\omega_f = -12.6 rad/s

so final angular speed is -12.6 rad/s

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mass and weight are similar, but not the same thing. In which of the following examples would the objects weight change, but mas
OverLord2011 [107]

When an astronaut travels from the earth to the moon, her weight changes, but her mass remains constant.  <em>(C ).</em>

7 0
3 years ago
What is the atmospheric pressure and temperature at sea level in a standard<br> atmosphere?
Lady bird [3.3K]

Answer:

The tropospheric tabulation continues to 11,000 meters (36,089 ft), where the temperature has fallen to −56.5 °C (−69.7 °F), the pressure to 22,632 pascals (3.2825 psi), and the density to 0.3639 kilograms per cubic meter (0.02272 lb/cu ft). Between 11 km and 20 km, the temperature remains constant

Explanation:

Hope this helped, Have a wonderful day!!

4 0
2 years ago
1. Water boils at 100°C at sea level. If the water in this experiment did not boil at 100°C, what could be the reason?
umka2103 [35]

Answer:

It may not be at the sea level

Explanation:

The reason here is water only boils at sea level. This means that if you move water to a different height, say top of a mountain, the boiling temperature of water would change. This is due to the pressure drop at high place. The drop of pressure would make it harder to transform water liquid to gas, thus requiring more temperature.

8 0
3 years ago
Read 2 more answers
A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a
Bess [88]

Answer:

Mass = 1.99 * 10^{30} kg

Explanation:

Given

Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg

Required

Rewrite using scientific notation

The format of a number in scientific notation is

Digit = a * 10^n

Where 1 \geq\ a\geq\ 10

So the given parameter can be rewritten as

Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg

Express as a power of 10

Mass = 1.99 * 10^{30} kg

Hence, the equivalent of the mass of the sun in scientific notation is:

Mass = 1.99 * 10^{30} kg

7 0
3 years ago
un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en l
Dmitriy789 [7]

Answer:

Acceleration = 5.77 m/s²

Distance cover in 13 seconds = 487.56 meter

Explanation:

Given:

Final velocity of mobile device = 75 m/s

initial velocity of mobile device = 0 m/s

Time taken = 13 seconds

Find:

Acceleration

Distance cover in 13 seconds

Computation:

v = u + at

75 = 0 + (a)(13)

13a = 75

a = 5.77

Acceleration = 5.77 m/s²

s = ut + (1/2)(a)(t²)

s = (0)(t) + (1/2)(5.77)(13²)

Distance cover in 13 seconds = 487.56 meter

8 0
3 years ago
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