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3 years ago

What is the advantage of having nuclear physics?

Physics

2 answers:

rusak2 [61]3 years ago

6 0

Answer:

Nuclear physics is usually defined as a branch of physics that deals with the study of the atomic nucleus. This study of the atomic nucleus is the main key to the understanding of the creation and evolution of the universe. It helps in finding the answers that are related to nuclear physics and enhances the understanding capacity of an individual and also gains knowledge regarding any small or large topic.

This subject of nuclear physics is commonly used in the field of medical science and also used in the construction of weapons.

LekaFEV [45]3 years ago

5 0

Nuclear physics<span> is the study of the protons and neutrons at the centre of an atom and the interactions that hold them together in a space just a few femtometres (10-15 metres) across. It would be advantageous because we understand how atoms behave. Hope this answers the question.</span>

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A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a

Ilya [14]

Answer with Explanation:

We are given that

Area of loop= $(20\times 20) cm^2=400\times 10^{-4} m^2$

$1 cm^2=10^{-4} m^2$

Resistance, R= $0.1\Omega$

B= $4t-2t^2$

We know that magnetic flux

$\phi=BA$

Emf , $E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid$

Current, $I=\frac{E}{R}$

Current, $I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid$

Substitute t=0 s

Then, I= $1.6\mid (1-0)\mid$ =1.6 A

Substitute t=1 s

Then, I= $1.6\mid (1-1)\mid$ =0

Substitute

t=2 s

Current, I= $1.6\mid(1-2)\mid$ =1.6 A

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elena-s [515]

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The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o

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Answer:
frequency = 5.52 * 10² Hz

Explanation:
the equation that relates velocity, frequency and wavelength is:
velocity = frequency * wavelength

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velocity = 331 m/sec
wavelength = 0.6 m

Substitute with the givens in the equation to get the frequency as follows:
velocity = frequency * wavelength
331 = frequency * 0.6
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frequency = 5.52 * 10² Hz

Hope this helps :)

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Answer is 29.1 mol or 525 g

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