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Natalka [10]
3 years ago
10

Chemical reactions are only able to occur in one direction. Chemical reactions are only able to occur in one direction. True Fal

se
Chemistry
1 answer:
blagie [28]3 years ago
7 0

Answer:

False

Explanation:

While chemical reactions can proceed in the forward direction , they can in fact also proceed in the backward direction too. The direction they would proceed depends majorly on the state of chemical equilibrium at that particular time for that particular chemical reaction.

It should be known that when a chemical reaction proceeds in the forward way, more products are formed and the reactants are used up. If however, the chemical reaction proceed in the backward way, more reactants are formed and the products are used up.

A practical example is in the case of an exothermic reaction. This is one in which heat is released to the surroundings as a result of the reactants being at a higer energy level compared to the product. Now, depending on the prevailing equilibrium constraint, the reaction could proceed forward or backward.

If for example, the temperature is decreased, this is a constraint being applied to the equilibrium state. The chemical reaction would take a shift and will favor the forward reaction and more of the products will be formed. And also of the temperature is increased, it is the backward reaction that is favored

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Consider the reactions C2H4(g) + 2O2(g) → 2CO(g) + 2H2O(g) ∆H = −758 kJ mol−1 2C(s) + 2H2(g) → C2H4(g) ∆H = +52 kJ mol−1 H2(g) +
Lilit [14]

C2H4(g) + 2O2(g) → 2CO(g) + 2H2O(g)       ∆H1 = −758 kJ mol−1       ....1)

2C(s) + 2H2(g) → C2H4(g)                           ∆H2 = +52 kJ mol−1        ....2)

H2(g) + O2(g) → H2O(g)                               ∆H3 = −242 kJ mol−1     ....3)

Now, enthalpy of formation of carbon monoxide is given by :

∆H = ∆H1 + ∆H2 - ∆H3

∆H = ( -758 + 52 - ( -242 ) ) kJ mol−1  

∆H = −464 kJ mol−1

Therefore, the enthalpy of formation of carbon monoxide is -464 kJ mol−1.

Hence, this is the required solution.

4 0
2 years ago
Which word part means cold?<br> crylo<br> chem/<br> cis/o<br> cyan/
snow_lady [41]
Crylo i think is the correct answer
8 0
3 years ago
3. How did earthquakes help scientists to understand the structure of the earth's crust?​
Fantom [35]

Answer:

i hace no idea sorry

Explanation:

i do motor know the awnser

4 0
2 years ago
If 850. mL of linseed oil has a mass of 620. g, calculate the density of linseed oil.
meriva

Answer:

<h3>The answer is 0.73 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 620 g

volume = 850 mL

We have

density =  \frac{620}{850}   \\  = 0.7294117647...

We have the final answer as

<h3>0.73 g/mL</h3>

Hope this helps you

3 0
2 years ago
calculate the mass of calcium phosphate and the mass of sodium chloride that could be formed when a solution containing 12.00g o
Leviafan [203]

Answer : The mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

Explanation : Given,

Mass of Na_3PO_4 = 12.00 g

Mass of CaCl_2 = 10.0 g

Molar mass of Na_3PO_4 = 164 g/mol

Molar mass of CaCl_2 = 111 g/mol

Molar mass of NaCl = 58.5 g/mol

Molar mass of Ca_3(PO_4)_2 = 310 g/mol

First we have to calculate the moles of Na_3PO_4 and CaCl_2.

\text{Moles of }Na_3PO_4=\frac{\text{Given mass }Na_3PO_4}{\text{Molar mass }Na_3PO_4}

\text{Moles of }Na_3PO_4=\frac{12.00g}{164g/mol}=0.0732mol

and,

\text{Moles of }CaCl_2=\frac{\text{Given mass }CaCl_2}{\text{Molar mass }CaCl_2}

\text{Moles of }CaCl_2=\frac{10.0g}{111g/mol}=0.0901mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is:

2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2

From the balanced reaction we conclude that

As, 3 mole of CaCl_2 react with 2 mole of Na_3PO_4

So, 0.0901 moles of CaCl_2 react with \frac{2}{3}\times 0.0901=0.0601 moles of Na_3PO_4

From this we conclude that, Na_3PO_4 is an excess reagent because the given moles are greater than the required moles and CaCl_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NaCl  and Ca_3(PO_4)_2

From the reaction, we conclude that

As, 3 mole of CaCl_2 react to give 6 mole of NaCl

So, 0.0901 mole of CaCl_2 react to give \frac{6}{3}\times 0.0901=0.1802 mole of NaCl

and,

As, 3 mole of CaCl_2 react to give 1 mole of Ca_3(PO_4)_2

So, 0.0901 mole of CaCl_2 react to give \frac{1}{3}\times 0.0901=0.030 mole of Ca_3(PO_4)_2

Now we have to calculate the mass of NaCl  and Ca_3(PO_4)_2

\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl

\text{ Mass of }NaCl=(0.1802moles)\times (58.5g/mole)=10.5g

and,

\text{ Mass of }Ca_3(PO_4)_2=\text{ Moles of }Ca_3(PO_4)_2\times \text{ Molar mass of }Ca_3(PO_4)_2

\text{ Mass of }Ca_3(PO_4)_2=(0.030moles)\times (310g/mole)=9.3g

Therefore, the mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

5 0
3 years ago
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