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Serhud [2]
3 years ago
7

Explain why a plant may look green in sunlight but under red lighting

Physics
1 answer:
umka2103 [35]3 years ago
8 0

plants look green in sunlight because, all other colors except green are absorbed by the plants and only green color is reflected back, hence plants look green in sunlight.

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A coil of wire with 60 turns lies on the plane of the page, and a uniform magnetic field points into the page with a strength of
baherus [9]

Answer:

0.85V

Explanation:

The emf is calculated by using the Lenz's Law

\epsilon=-\frac{\Delta\Phi_B}{\Delta t}

But for this case we have that the magnetic field is constant. Hence we have

\epsilon=-\frac{B(A_{2}-A_{1})}{t_2-t_1}=-\frac{(1.10T)(0.270m^{2}-0.89m^{2})}{0.8s}\\\\\epsilon=0.85V

where we have taken that the intial time is t1=0

I hope this is useful for you

regards

4 0
3 years ago
Any help please, physics is not my strong suit?
frez [133]

Answer:

2000mg = 2g

5L = 5000mL

16cm = 160mm

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3 years ago
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a firework rock is burning at the rate of 14g/s all the products of combustion are ejected in one direction at the speed of 210m
Naddika [18.5K]

SO MY NAME IS ROHITH AND I LIKE MM

Explanation:

5 0
3 years ago
Need Some Help Please :)
joja [24]
1. The amount of energy carried by the wave is related to the Amplitude of the wave.
2. A mechanical wave requires an initial energy input, Once this initial energy is added the wave travels through the medium until all it's energy is transferred.
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A garden hose with a diameter of 0.64 in has water flowing in it with a speed of 0.46 m/s and a pressure of 1.9 atmospheres. At
STALIN [3.7K]

Answer:

(a).The speed of the water in the nozzle is 3.014 m/s.

(b). The pressure in the nozzle is 1.86 atm.

Explanation:

Given that,

Nozzle diameter = 0.25 in = 0.00635 m

Hose pipe diameter = 0.64 in = 0.016256 m

Pressure = 1.9 atm =192518 Pa

(a). We need to calculate the speed of the water in the nozzle

Flow Speed at the inlet pipe will be given by using Continuity Equation

Q_{1}=Q_{2}

v_{1}A_{1}=v_{2}A_{2}

v_{1}=v_{2}\times(\dfrac{A_{2}}{A_{1}})

Where, A = area of pipe

A=\pi\times \dfrac{d^2}{4}

v_{1}=v_{2}\times(\dfrac{d_{2}^2}{d_{1}^2})

Put the value into the formula

v_{1}=0.46\times\dfrac{(0.016256)^2}{(0.00635)^2}

v_{1}=3.014\ m/s

The speed of the water in the nozzle is 3.014 m/s.

(b). We need to calculate the pressure in the nozzle

Using Bernoulli's Theorem,

P_{1}+\dfrac{1}{2}\rho\times v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2+\rho gh_{2}

Where, h_{1}=h_{2}

P_{1}+\dfrac{1}{2}\rho\times v_{1}^2=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2

P_{1}=P_{2}+\dfrac{1}{2}\rho(v_{2}^2-v_{1}^2)

Put the value into the formula

P_{1}=192518 +\dfrac{1}{2}\times1000\times((0.46)^2-(3.014)^2)

P_{1}=188081.702\ Pa

P=1.86\ atm

Hence, (a).The speed of the water in the nozzle is 3.014 m/s.

(b). The pressure in the nozzle is 1.86 atm.

7 0
3 years ago
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