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Flauer [41]
3 years ago
6

Why are hydrophobic molecules such as fats and oils unable to dissolve in watery solutions?

Chemistry
1 answer:
Maru [420]3 years ago
6 0
Hydrophobic mplecules are unable to fissolve in watery solution becuse they dislike water.

Hydro= water
-phobic= fear

Hydrophobic= fear of water, or disliking water
*Think of it like this:
when you mix oil and water, do they mix, or does oil float at the top?

If your reply is "oil float to the top", then you're right. Oil and water DOES NOT mix together. Hope that help!
You might be interested in
Need some help with this problem please!
Tom [10]

Answer:

18 liters

Explanation:

Step 1: Figure out what the formula and what you are dealing with.

- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.

- P1 = 1 atm

- P2 = 20 atm

- V1 = 360 liters

- V2 = trying to find

Note: remember the original equation is V1/P1 = V2/P2

- Step 2: Rearrange the equation to fit this problem, you should get...

V2 = V1 x P1 / P2

- Step 3: Fill our own numbers in. You should get...

360 L x 1 atm / 20 atm = 18 Liters (do the math)

- Answer = 18 Liters

- Remember to just follow the formula and fill it in with your own numbers.

If you need any more help comment below. I am happy to help anytime.

7 0
3 years ago
Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C
taurus [48]

Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

Q_1=-Q_2

In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}

Then, plug in the masses, specific heat and temperatures to obtain:

T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

4 0
3 years ago
Relative to the mass of the nucleous of a atom. the mass of electron is​
Paladinen [302]
The number of protons found in the nucleus equals the number of electrons that surround it, giving the atom a neutral charge (neutrons have zero charge). Most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen.Hoped this helped
5 0
3 years ago
Choose the answer that best explains why α–pyrone reacts with br2 to yield a substitution product (like benzene does), rather th
meriva

As can be seen in the attached image, α-pyrone has a highly electrophilic carbon atom, since it is attached to two oxygen atoms that are electronegative and subtract electrical charge from the carbon, leaving it with a <u>positive partial charge</u>. By virtue of the above, <u>the bromine atoms, which have an important electron density that makes them good nucleophiles, will be attracted to the aforementioned carbon due to their positive charge</u>, thus favoring the substitution product to a greater extent than that of addition.

7 0
3 years ago
If the amount of copper is 6g and whole ratio to obtain copper sulfide is 4:1. How much sulfur is required for the reaction to o
Yuki888 [10]

Answer:

1.5g

Explanation:

According to this question, the amount of copper required to obtain copper sulfide in a 4:1 is 6g. This means that the ratio of copper to sulfur in the compound (copper sulfide) is 4:1.

Hence, to calculate the amount of sulfur required for the reaction to obtain copper sulfide using the above ratio, we say:

1/4 of the amount of copper required (6g)

= 1/4 × 6

= 6/4

= 1.5g of sulfur is required for the reaction to obtain carbon sulfide.

4 0
2 years ago
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