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Rainbow [258]
3 years ago
8

Hi can you please help me, im really stuck

Physics
1 answer:
Lady bird [3.3K]3 years ago
3 0
I have the answer for A. Since there is blockage in the ear canal, some sound waves may not be able to get through or travel as quickly so you would have trouble hearing
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What are the steps to extract metal from the earths crust
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<span>Methods of extraction include: extract by electrolysis, extract by reaction with carbon or carbon monoxide, and extracted by various chemical reactions.</span>
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3 years ago
Two friends are having a conversation. Anna says a satellite in orbit is in freefall because the satellite keeps falling toward
Leno4ka [110]

Answer:

Anna is correct.

Explanation:

Anna is right as a satellite is in free fall because it keeps falling toward Earth, meaning that gravity is the only force acting on it. Tom is incorrect because an object does not have to accelerate at a certain speed to be considered to be in free fall. As long as gravity is the only force acting upon the object, it is considered to be in free fall.

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julie is cycling at a speed of 3.4 meters/second. if the combined mass if the bicycle and julies is 30 kilograms. what is the ki
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3 0
3 years ago
Sound waves in air travel at approximately 330m/s. Calculate the frequency of a 2.5m-long sound wave.
dusya [7]
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8 0
3 years ago
shows two parallel nonconducting rings with their central axes along a common line. Ring 1 has uniform charge q1 and radius R; r
Ainat [17]

Answer:

\dfrac{q_1}{q_2}=2\left(\dfrac{2}{5}\right )^{3/2}

Explanation:

Given that

Charge on ring 1 is q1 and radius is R.

Charge on ring 2 is q2 and radius is R.

Distance ,d= 3 R

So the total electric field at point P is given as follows

Given that distance from ring 1 is R

\dfrac{1}{4\pi\epsilon _o}\dfrac{q_1R}{(R^2+R^2)^{3/2}}-\dfrac{1}{4\pi\epsilon _o}\dfrac{q_2(d-R)}{(R^2+(d-R)^2)^{3/2}}=0

\dfrac{1}{4\pi\epsilon _o}\dfrac{q_1R}{(R^2+R^2)^{3/2}}-\dfrac{1}{4\pi\epsilon _o}\dfrac{q_2(3R-R)}{(R^2+4R^2)^{3/2}}=0

\dfrac{q_1R}{(2R^2)^{3/2}}-\dfrac{q_2(2R)}{(5R^2)^{3/2}}=0

\dfrac{q_1}{q_2}=2\left(\dfrac{2}{5}\right )^{3/2}

8 0
3 years ago
Read 2 more answers
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