The maximum transverse force on a 1.00cm segment of the string is 0.045N.
The maximum transverse force on the segment,
l=1.00cm=1.00cm×1m/100cm=0.01m is,
F=μla
=(12.0×10^−3kg/m)×(0.01m)×(375m/s^2)
=0.045N
Hence the maximum force is 0.045N
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Answer:
Rita runs faster
Explanation:
To obtain the answer to the question given, we determine the speed of Rita. This can be obtained as follow:
Distance = 1.6 km
Time = 15 mins
Speed =?
Next, we shall convert 15 mins to hour. This can be obtained as follow:
60 mins = 1 h
Therefore,
15 mins = 15 mins × 1 h / 60 mins
15 mins = 0.25 h
Thus, 15 mins is equivalent to 0.25 h.
Finally, we shall determine speed of Rita as follow:
Distance = 1.6 km
Time = 0.25 h
Speed =?
Speed = distance / time
Speed = 1.6 / 0.25
Speed = 6.4 Km/h
Thus Rita's speed is 6.4 Km/h
Comparing the speed of Rahul and Rita
Rahul's speed = 4.5 km/h
Rita's speed = 6.4 Km/h
We can see that Rita's speed is greater than Rahul's speed. This simply indicates that Rita runs faster than Rahul.
Answer:
3.66m/s^2
Explanation:
First, we need to find the friction which is F=u*N.
After that, find the resultant force by substarcting the friction from the forward force.
Lastly,using the formula F=ma, substitute in the known values of F and m to find a
Answer:
A negative charge, if free to move in an electric field, will move from a low potential point to a high potential point. To move a positive charge against the electric field, work has to be done by you or a force external to the field.
Explanation:
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