I believe its air particles
Answer:
1.2 A of current will send (3.744 × 10¹⁸) ions to the cathode per second.
Explanation:
According to Faraday's second law of electrolysis, the amount of ions/mass of substance deposited at an electrode depends on its equivalent weight.
For a divalent ion, it will require 2F of electricity per mole.
1 F = 96500 C
Amount of electricity that passes through the electrolyte per second = (magnitude of current) × (time) = It = (1.2 × 1) = 1.2 C
2F (2×96500C) of electricity will deposit 1 mole of Copper ions
That is,
193000 C of electricity will deposit 1 mole of Copper.
1.2 C will deposit (1.2×1/193000); 0.0000062176 mole of Copper.
1 mole of Copper contains (6.022 × 10²³) ions according to the Avogadro's constant.
0.0000062176 mole of Copper will contain (0.0000062176 × 6.022 × 10²³) ions = (3.744 × 10¹⁸) ions.
Therefore, 1.2 A of current will send (3.744 × 10¹⁸) ions to the cathode per second.
Hope this Helps!!!
Answer:
v= 17.15 m/s
Explanation:
mass of the book=0.1 Kg
height above ground, h= 15 m
Using conservation of energy
Potential energy is converted into kinetic energy
![mgh = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=mgh%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![v=\sqrt{2gh}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2gh%7D)
![v=\sqrt{2\times 9.8\times 15}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%5Ctimes%209.8%5Ctimes%2015%7D)
![v=\sqrt{294}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B294%7D)
v= 17.15 m/s
Hence, the book will hit the ground at the speed of 17.15 m/s.
Idk since it looks sooooo close ,but is it is that’s really cool
I believe the answer would be A) Centripetal force.