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kirill115 [55]
4 years ago
12

Radiation emitted from human skin reaches its peak at λ = 940 µm. (a) What is the frequency of this radiation? (b) What type of

electromagnetic waves are these? (c) How much energy (in electron volts) is carried by one quantum of this radiation?

Physics
1 answer:
laiz [17]4 years ago
8 0

Answer:

a) the frequency is 3.191x10^11

b)the radiation is a microwave radiation

c) the energy of one quantum of this radiation is 1.32x10^-3ev

Explanation:

Detailed explanation and calculation is shown in the image below

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The average Intensity of the electromagnetic field due to sunlight at the surface of the earth is 1400 W/m^2. Calculate the maxi
Ann [662]

Answer:

1027 N/C

3.42 x 10⁻⁶ T

Explanation:

I = Intensity of electromagnetic field = 1400 W/m²

E₀ = Maximum value of electric field

Intensity of electromagnetic field is given as

I = (0.5) ε₀ E₀² c

1400 =  (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²

E₀ = 1027 N/C

B₀ = maximum value of magnetic field

using the equation

E₀ = B₀ c

1027 = B₀ (3 x 10⁸)

B₀ = 3.42 x 10⁻⁶ T

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3 years ago
Which action may cause ripple marks in layers of rocks? A. strong pressure over time B. gradual heating C. accelerated cooling D
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D rapid water movement
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3 years ago
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An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an elect
klio [65]

Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

Answer:

The magnetic field strength is  B= 0.0048 T

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

                             \Delta V q = \frac{1}{2}mv^2

      Making v the subject

                             v = \sqrt{[\frac{2 \Delta V * q }{m}] }

 Where m is the mass of electron

              v is the velocity of electron

              q charge on electron

               \Delta V is the potential difference  

Substituting values

         v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }f

            = 4.5556 *10^ {7} m/s

For the electron to move in a circular path the magnetic force[F = B q v] must be equal to the centripetal force[\frac{mv^2}{r}] and this is mathematically represented as

                  Bqv = \frac{mv^2}{r}

making B the subject

                B = \frac{mv}{rq}

r is the radius with a value = 5.4cm = = \frac{5.4}{100} = 5.4*10^{-2} m

Substituting values

                B = \frac{9.1039 *10^{-31} * 4.556 *10^7}{5.4*10^-2 * 1.60218*10^{-19}}

                     = 0.0048 T

                 

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4 years ago
Which list contains only objects that orbit the sun in our solar system?
Andre45 [30]

The answer would be C.

3 0
4 years ago
MacGyver is riding on a skateboard and moving west of the velocity of 7 m/s. Macgyver has a mass of 92 kg and the skateboard has
ivann1987 [24]

Answer:

64.5

Explanation:

(m1 + m2) v initial = (m1 * v1 final) + (m2 * v2 final)

(92 + 8)(-7) = (92 x 2) + (8 x v2 final)

(100)(-7) = (184) + (8 x v2 final)

-700 = (184) +  (8 x v2 final)

-516 =  (8 x v2 final)

-516/8 = v2 final

-64.5 = v2 final

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3 years ago
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