I would believe sunlight to be an independent variable as the sunlight is the control of the whole experiment. You can tell because he placed one in a dark area and the other in a sunny area.
The dependent variable would be: Growth
Controls: The air-conditioning in both rooms
It is not constant because this would be the variable that would remain the same, for example, the type of plant was kept the same.
Hope this helps c:
They are called lanthanoids!
Phosphoric acid forms three classes of salts corresponding to replacement of one, two, or three hydrogen atoms. Among the important phosphate salts are: sodium dihydrogen phosphate (NaH2PO4), used for control of hydrogen ion concentration (acidity) of solutions; disodium hydrogen phosphate (Na2HPO4), used in water treatment as a precipitant for highly charged metal cations; trisodium phosphate (Na3PO4), used in soaps and detergents; calcium dihydrogen phosphate or calcium superphosphate (Ca[H2PO4]2), a major fertilizer ingredient; calcium monohydrogen phosphate (CaHPO4), used as a conditioning agent for salts and sugars.
Answer:
Explanation:
From the given information;
Let Q(t) = mass of dye in the tank as a function of time
The mass in the tank = 200 L × (1g/L) = 200 g
Using the law of mass conservation;
Q(0) = 200
By finding the solution to the ODE using the method of separation of variables;
Using the initial condition;
200 = Q(0) = C
1% of 200g = 2g of dye solution
∴
t = 460.5 hours
<h3>
Answer:</h3>
4649.16 g
<h3>
Explanation:</h3>
We are given;
- The equation for the reaction
2C₄H₁₀ + 13O₂→ 8CO₂ + 10H₂O
We are required to determine the mass of water produced.
<h3>
Step: Determine the number of moles of C₄H₁₀</h3>
We know that, moles = Mass ÷ Molar mass
Molar mass of C₄H₁₀ is 58.14 g/mol
Therefore;
Moles of C₄H₁₀ = 3000 g ÷ 58.14 g/mol
= 51.5996
= 51.60 moles
<h3>Step 2: Determine the number of moles of water </h3>
- From the equation, 2 moles of C₄H₁₀ reacts to produce 10 moles of water
Therefore;
Moles of water = Moles of C₄H₁₀ × 10/2
= 51.60 moles × 5
= 258 moles
<h3>Step 3: Determine the mass of water produced </h3>
We know that; mass = moles × molar mass
Molar mass of water = 18.02 g/mol
Thus;
Mass of water = 258 moles × 18.02 g/mol
= 4649.16 g
Therefore, the mass of water produced will be 4649.16 g