All categories

3 years ago

1 mole of nacl(s) has a greater entropy than 1 mole of nacl(aq). true or false g

1 answer:

3 0

It is false that 1 mole of nacl(s) has a greater entropy than 1 mole of nacl (aq).

this is because nacl(aq) is in aqueous state while nacl(s) is in solid state. Nacl(aq) has greater entropy than nacl(s) because in
aqueous state their is increase in entropy. the entropy of the two ions in water has greater entropy than the solid nacl.

You might be interested in

Calculate the concentration in mol L^-1 of ammonium ions in a solution prepared by mixing 360 mL of 0.250 mol L^-1 ammonium sulf

Mnenie [13.5K]

In order to determine the concentration of ammonium ions in the solution prepared by mixing solutions of ammonium sulfate, (NH4)2SO4, and ammonium nitrate, first calculate the amount of ammonium ions for each solution.

For ammonium sulfate sol'n: 0.360 L x 0.250 mol(NH4)2SO4/ L x 2 mol NH4+ /1 mol(NH4)2SO4 = 0.18 mol NH4+
For ammonium nitrate sol'n: 0.675 x 1.2 mol NH4NO3/L x 1 mol NH4+ /1 molNH4NO3 = 0.81 mol NH4+

Thus, the amount of NH4+ ions is (0.18 + 0.81) mol or 0.99 mol NH4+. To get the concentration, multiply this to the volume of solution which is assumed to be additive, such that:

M NH4+ in sol’n = 0.99 mol NH4+/1.035 L = 0.9565 mol NH4+/ L sol’n

8 0

3 years ago

How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg

Afina-wow [57]

Answer : The mass of $PbSO_4$ needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of $PbCrO_4$ .

$\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole$

Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

Now we have to calculate the mass of $PbSO_4$

$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

$\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g$

Therefore, the mass of $PbSO_4$ needed are, 1.515 grams.

6 0

2 years ago

Which scientists contributed to the current model of the atom? And what was their contribution?

Lina20 [59]

Binuk, Drew, Henry, Liz Scientists who contributed in the Atomic Theory Robert Andrews Millikan James Chadwick Used an oil-drop experiment to measure the charge of the electron, allowing them then to be able to calculate the mass of the electron.

4 0

3 years ago

If an element has 2+ valence electrons, does it transfer only one or more than one valence electrons

just olya [345]

Answer:

element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.

Explanation:

Group IIA have 2+ valency and two electrons in its valance shell.

Its Electropositivity is high and have the tendency to donate it two electrons.

Element of IIA form ionic with most electronegative element.

Examples:

Cu²⁺, Mg²⁺, Sr²⁺ are examples having 2+ valance electron

one of the following is examples of element that have 2+ valence electrons

MgCl₂

Atomic number of Magnesium (Mg) is 12

Electronic Configuration of Mg:

1s², 2s², 2p⁶, 3s²

K =2

L = 8

M = 2

So, it have to give its 2 electrons to form a stable compound.

Similarly

Chlorine atomic number is 17

Electronic Configuration of Chlorine:

1s², 2s², 2p⁶, 3s², 3p⁵

K =2

L = 8

M = 7

So, it have to gain one electrons to form a stable compound and complete its octet.

So,

Two chlorine atom as a molecule gain 2 electrons from Mg²⁺ atom

So one Mg²⁺ and 2 Cl⁻ atoms form an ionic bond

where in this ionic bond Mg²⁺ transfer its 2 valence electron completely and chlorine molecule accept 2 electrons.

Cl-----Mg------Cl

So the Answer is

element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.

8 0

2 years ago

Determine the mass of each sample 1.55 kmol sulfur trioxide

xxMikexx [17]

Explanation:

Given parameters:

Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole

Unknown:

Mass of the sulfur trioxide = ?

Solution:

To solve for the mass of the sample of sulfur trioxide:

Find the molar mass of the compound i.e SO₃

atomic mass of S = 32g

O = 16g

molar mass = 32 + 3(16) = 80g/mol

Use the formula below:

mass of SO₃ = number of moles x molar mass

mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg

Learn more:

mole calculation brainly.com/question/13064292

#learnwithBrainly

3 0

3 years ago