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3 years ago

1 mole of nacl(s) has a greater entropy than 1 mole of nacl(aq). true or false g

1 answer:

3 0

It is false that 1 mole of nacl(s) has a greater entropy than 1 mole of nacl (aq).

this is because nacl(aq) is in aqueous state while nacl(s) is in solid state. Nacl(aq) has greater entropy than nacl(s) because in
aqueous state their is increase in entropy. the entropy of the two ions in water has greater entropy than the solid nacl.

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The atomic mass of an element is equal to the:

Stells [14]

Answer:

number of protons and neutrons

Explanation:

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3 years ago

Read 2 more answers

Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the

Alecsey [184]

Explanation:

The chemical equation is as follows.

$\frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)$

And, the given enthalpy is as follows.

$\frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g)$ ; $\Delta H$ = 102.5 kJ

Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

$\Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}$

102.5 = $[(\frac{1}{2})x + 498] - [(2)(243)]$

102.5 = $(\frac{1}{2})x + 498 - 486$

102.5 - 12 = $\frac{x}{2}$

x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

$\Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})$

x = $[(\frac{1}{2})181 + (\frac{1}{2})498] - 243$

= 339.5 - 243

= 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

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3 years ago

If a plant cell was an office building what were the chloroplasts be? (and why?)

Ierofanga [76]

This would be the coffee machine in the break room. Because the chloroplast creates energy from the sun. and this creates energy from coffee beans to give to the employees

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4 years ago

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4 years ago

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balu736 [363]

Answer:

In every sequence even numbers are added in order.

3, 5, 9, 15, 23, 33