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Ludmilka [50]
3 years ago
11

1 mole of nacl(s) has a greater entropy than 1 mole of nacl(aq). true or false g

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
3 0
It  is  false   that  1  mole  of  nacl(s)  has  a  greater  entropy  than   1  mole  of  nacl (aq).  

  this  is  because    nacl(aq)   is  in  aqueous  state  while  nacl(s)  is  in  solid  state.  Nacl(aq)  has  greater  entropy  than  nacl(s)  because    in 
aqueous   state  their   is  increase  in  entropy. the  entropy   of  the  two  ions  in  water  has   greater  entropy  than  the  solid   nacl.
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Rank the members of each set of compounds according to the ionic character of their bonds. Most ionic bonds?a) PCl3 PBr3 PF3 Mos
SCORPION-xisa [38]

Explanation:

More is the electronegativity difference between the combining atoms more polar is the compound. Hence, more ionic it will be in nature.

(a)   Electronegativity value of P = 2.19

Electronegativity value of Cl = 3.16

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a P-Cl bond = 3.16 - 2.19 = 0.97

Electronegativity difference of a P-Br bond = 2.96 - 2.19 = 0.77

Electronegativity difference of a P-F bond = 3.98 - 2.19 = 1.79

Since, a P-F bond has the highest electronegativity difference. Therefore, PF_{3} is the most ionic compound and PBr_{3} is the least ionic compound.

(b)   Electronegativity value of B = 2.04

Electronegativity value of N = 3.04

Electronegativity value of C = 2.55

Electronegativity value of F = 3.98

Electronegativity difference of a B-F bond = 3.98 - 2.04 = 1.94

Electronegativity difference of a N-F bond = 3.04 - 3.98 = 0.94

Electronegativity difference of a C-F bond = 3.98 - 2.55 = 1.43

Since, a B-F bond has the highest electronegativity difference. Therefore, BF_{3} is the most ionic compound and NF_{3} is the least ionic compound.

(c)   Electronegativity value of Se = 2.55

Electronegativity value of Te = 2.1

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a Se-F bond = 3.98 - 2.55 = 1.43

Electronegativity difference of a Te-F bond = 3.98 - 2.1 = 1.88

Electronegativity difference of a Br-F bond = 3.98 - 2.19 = 1.02

Since, a Te-F bond has the highest electronegativity difference. Therefore, TeF_{4} is the most ionic compound and BrF_{3} is the least ionic compound.

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3 years ago
n a combination redox reaction, two or more ____________ , at least one of which is a(n) ____________ , form a(n) ____________ .
Anna [14]

Answer:

In a combination redox reaction, two or more reactants, at least one of which is a(n) element, form a(n) compound. General Reaction: X + Y > Z

In a decomposition redox reaction, a(n) compound forms two or more products, at least one of which is a(n) element. General Reaction: Z>X+Y

In double-displacement (metathesis) reactions, such as precipitation and acid-base reactions, atoms (or ions) of two compounds exchange places; these reactions are not redox processes. General Reaction: AB+CD>AD+CB

In solution, single-displacement reactions occur when a(n) atom of one element displaces the atom of another. Since one of the reactants is a(n) element, all single-displacement reactions are redox processes. General Reaction: X+YZ>XY+Z

Explanation:

In a combination redox reaction, two or more reactants, at least one of which is a(n) element, form a(n) compound.

General Reaction: X + Y > Z

In the reaction scheme above, X combines with Y to give Z as a product.

In a decomposition redox reaction, a(n) compound forms two or more products, at least one of which is a(n) element.

General Reaction: Z>X+Y

In the reaction scheme above, Z decomposes to X and Y

In double-displacement (metathesis) reactions, such as precipitation and acid-base reactions, atoms (or ions) of two compounds exchange places; these reactions are not redox processes since there are no changes occurring in the oxidation number of the atoms (or ions) involved.

General Reaction: AB+CD>AD+CB

In the reaction scheme above, B and D exchange places in their respective compounds

In solution, single-displacement reactions occur when a(n) atom of one element displaces the atom of another. This type of reaction is due to the difference in the reactivities of the elements. The more reactive atom of one element displaces the least reactive atom of another element from its solution.

Since one of the reactants is a(n) element, all single-displacement reactions are redox processes.

General Reaction: X+YZ>XY+Z

In the reaction scheme above, X displaces Z from the compound YZ.

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Answer: melting points are major means of identifying pure compounds.

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A pure compound can be identified by its melting point because, a pure compound will have a sharp melting point while an impure compound will melt over a temperature range. If presented with a pure sample of an unknown solid, its melting point can tell us what the identity of the compound. Similarly, melting point analysis can show the purity of a known solid. If the known solid has a sharp melting point, then it is pure.

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