Atomic radius and electronegativity trends are...
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When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.
Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.
In other words osmolarity is the multiple if molarity
Osmolarity = i× molarity
Here i represents the van't Hoff factor,
⇒
3 Moles of + 1 mole
= 4
The number of moles of particles of solute produced in solution are actually called osmoles.
As a result, the van't Hoff factor will be equal to
i=4 Moles ions produced (osmoles) 1mole .dissolved =4
Since we know that,
=
Osmolarity =
=
Thus, the Osmolarity of given solution is 0.008 osmol/L.
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The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Data;
- Volume of solution = 260mL
- conc. of HCHO2 = 2.5*10^-2M
- conc. of NaCHO2 = 2.5*10^-2M
To calculate the mass of reagent added, let's start with HCHO2
The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.
The mass of NaCHO2 to be added in the buffer solution is
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Learn more about buffer solution here;
Answer: The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.
Explanation:
Activation energy is the extra amount of energy required by the reactants to cross the energy barrier to get converted into products.
When a catalyst is added, it lowers down the activation energy which is shown by a dotted line. As now less energy is required, more of reactants can cross the energy barrier and get converted to products and thus increase the rate of reaction.
A catalyst increases the rate of reaction for both exothermic and endothermic reactions.
