Atomic radius and electronegativity trends are...

Can somebody plz tell me which one I should circle for each question thanks!!!

marusya05 [52]

Answer:

1. False

2. True

3. True

4. True

5. False

Explanation:

7 0

3 years ago

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13 This word describes the circulatory system that provides nutrients and oxygen to living cells of the body.

Nina [5.8K]

Answer: Cardiovascular System

Explanation:

This involves your heart, blood, veins, and arteries

4 0

3 years ago

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

Answer: The value of equilibrium constant for the given reaction is 56.61

Explanation:

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 0.1 0.1

At eqllm: 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0

3 years ago

At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo

RoseWind [281]

Answer:

$[SO_3]=0.25M$

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

$[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}$

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

$[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\$

$[SO_3]=0.25M$

Best regards!

4 0

3 years ago

A homogeneous mixture is made by dissolving some salt in a beaker of water. The mixture is referred to as a

CaHeK987 [17]

In that case, the salt would be the solvent and the water the solute.
So, it would be solution!

Have a nice day! :D

3 0

3 years ago

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