Answer:
<h2>76°</h2>Explanation:
In projectile,
Maximum height = and range =
u = velocity of the body
= angle of launch
g = acceleration due to gravity
If the range equals the maximum height in an ideal projectile launch on a horizontal plane, this means;
since
The angle at which the range equals the maximum height in an ideal projectile launch on a horizontal plane is approximately 76°
(a) 764.4 N
The weight of the astronaut on Earth is given by:
where
m is the astronaut's mass
g is the acceleration due to gravity
Here we have
m = 78.0 kg
g = 9.8 m/s^2 at the Earth's surface
So the weight of the astronaut is
(b) 21.1 N
The spacecraft is located at a distance of
from the center of Earth.
The acceleration due to gravity at a generic distance r from the Earth's center is
where G is the gravitational constant and M is the Earth's mass.
We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:
(1)
the acceleration due to gravity at r=6R instead will be
And substituting (1) into this formula,
So the weight of the astronaut at the spacecratf location is