Answer:
Explanation:
Given
Three charges of magnitude q is placed at three corners and fourth charge is placed at last corner with -q charge
Force due to the charge placed at diagonally opposite end on -q charge
where Distance between the two charges
negative sign indicates that it is an attraction force
Now remaining two charges will apply the same amount of force as they are equally spaced from -q charge
The magnitude of force by both the charge is same but at an angle of
thus combination of two forces at 2 and 3 will be
Now it will add with force due to 1 charge
Thus net force will be
The answer is going to be element #29 Copper makes blue
Red:#38
Green:#56
Pink:#3
Yellow:#11
Gold:#20
Hopes This Helps
Answer: see the graph attached (straight line, passing through the origin and positive slope).
Justification:1)
Kinetic energy and temperature are in direct proportion. That means:
i) Being kinetic energy y and temperature x:
y α xii) That implies:
y = kx,where k is the constant of proportionality.
iii) The graph is a
line that passes through the origin and has positive slope k (k = y / x).2) The proportional relationship between kinetic energy (KE) and temperature (T) is shown by the
Boltzman law, which states:
Average KE = [3 / 2] KT, where K is Boltzman's constant, whose graph is of the form shown in the figure attached.
Answer:
1.
2.
Explanation:
1. According to Newton's law of motion, the puck motion is affected by the acceleration, which is generated by the push force F.
In Newton's 2nd law: F = ma
where m is the mass of the object and a is the resulted acceleration. So in the 2nd experiment, if we double the mass, a would be reduced by half.
Since the puck start from rest, in the 1st experiment, to achieve speed of v it would take t time
Now that acceleration is halved:
You would need to push for twice amount of time
2. The distance traveled by the puck is as the following equation:
So if the acceleration is halved while maintaining the same d:
As , then . Also
So t increased by 1.14
Yes, in general, metalloids are slightly reactive.