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riadik2000 [5.3K]

3 years ago

15

Which of the following elements do living things have that volcanic rocks don’t have? A) Oxygen B) Silicon C) Magnesium D) Carbo

n

1 answer:

Mrrafil [7]3 years ago

5 0

Either A or D. If I were answering I'd go with my git answer and say A

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Which quantity below is a derived quantity?

Reil [10]

By definition, the speed of an object is given by:

$v = \frac{dr}{dt}$

Where,

dr/dt: derived from the position with respect to time

Therefore, speed has units of length over units of time.

Thus, speed is a derived quantity, since it depends on the value of two other quantities.

Answer:

a derived quantity is:

C. Speed

4 0

3 years ago

Read 2 more answers

Select the false statement. A. Only materials that have never been part of a living thing can be recycled in nature. B. Matter f

astra-53 [7]

Option A is the false statement.

Only materials that have never been part of a living thing can be recycled in nature.

In actual all living and non living thing can be recycled in nature.

3 0

3 years ago

Saturated steam at 125 kpa is compressed adiabatically in a centrifugal compressor to 700 kpa at the rate of 2.5 kg⋅s−1. the com

Tpy6a [65]

M° = 2.5 kg/sec
For saturated steam tables
at p₁ = 125Kpa
hg = h₁ = 2685.2 KJ/kg
SQ = s₁ = 7.2847 KJ/kg-k
for isotopic compression
S₁ = S₂ = 7.2847 KJ/kg-k
at 700Kpa steam with S = 7.2847
h₂ 3051.3 KJ/kg
Compressor efficiency
h = 0.78
0.78 = h₂ - h₁/h₂-h₁
0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2
h₂ = 3154.6KJ/kg
at 700Kpa with 3154.6 KJ/kg
enthalpy gives
entropy S₂ = 7.4586 KJ/kg-k
Work = m(h₂ - h₁) = 2.5(3154.6 - 2685.2
W = 1173.5KW

5 0

3 years ago

The force an ideal spring exerts on an object is given by Fx = -kx, where x measures the displacement of the object from its equ

shusha [124]

Answer:

The work done by this force can be found via the following formula

$W = \int{F(x)} \, dx = \int\limits^0_{-20} {(-kx)} \, dx = \frac{-kx^2}{2}\left \{ {{x=0} \atop {x=-20}} \right. = \frac{-60*(-20)^2}{2} \\W = -12000J$

Explanation:

Alternatively, the work done by the object is equal to the elastic potantial energy done by the spring.

$U = \frac{1}{2}kx_2^2 - \frac{1}{2}kx_1^2 =0 - \frac{1}{2}60(-20)^2 = -12000J$

6 0

3 years ago

Two long straight parallel wires are separated by 7.0cm. There is a 2.0A current flowing in the first wire. If the magnetic fiel

aliina [53]

Answer:

The current in the second wire is 4.4 A.

Explanation:

Given that,

Distance =7.0 cm

Current in first wire = 2.0 A

The magnetic field strength is zero at distance of 2.2 cm from the first wire.

We need to calculate the current in the second wire

Using formula of magnetic field

$B=B_{1}-B_{2}$

$0=\dfrac{\mu_{0}I_{1}}{2\pi r_{1}}-\dfrac{\mu_{0}I_{2}}{2\pi r_{2}}$

$\dfrac{\mu_{0}I_{1}}{2\pi r_{1}}=\dfrac{\mu_{0}I_{2}}{2\pi r_{2}}$

$\dfrac{I_{1}}{r_{1}}=\dfrac{I_{2}}{(d-r_{1})}$

Here, $r_{2}=d-r_{1}$

$I_{2}=\dfrac{I_{1}\times(d-r_{1})}{r_{1}}$

Put the value into the formula

$I_{2}=\dfrac{2.0\times(7.0-2.2)}{2.2}$

$I_{2}=4.4\ A$

Hence, The current in the second wire is 4.4 A.

4 0

3 years ago