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liberstina [14]
2 years ago
10

What is its time interval between the release

Physics
1 answer:
azamat2 years ago
3 0
There are several many equations that are available to relate the distance,
speed, and time of a body moving vertically in gravity.  Happily, the only one
I can always remember without looking it up happens to be the right one to
use for this question !

             Distance  =  (1/2) x (gravity) x (time)²

                   3.8 m  =  (1/2) x (9.8 m/s²) x (time)²

Divide each side
by 4.9 m/s² :

                   (3.8 m) / (4.9 m/sec²)  =  (time)²

                     0.7755  sec²  =  time²

Square root
of each side:

                       0.88 second  =  time
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3 years ago
A 1.2 x 103 kg racecar, with a velocity of 8 m/s, collides with an unsuspecting 80 kg honey badger who is standing
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Answer: 90 m/s

Explanation:

Given

mass of racecar M=1.2\times10^3\ kg

velocity of racecar u=8\ m/s

mass of still honeybadger m=80\ kg

after collision race car is traveling at a speed of v_1=2\ m/s

conserving linear momentum

Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}]

1.2\times10^3\times8+0=1.2\times10^3\times2+80\times v_2

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