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liberstina [14]
3 years ago
10

What is its time interval between the release

Physics
1 answer:
azamat3 years ago
3 0
There are several many equations that are available to relate the distance,
speed, and time of a body moving vertically in gravity.  Happily, the only one
I can always remember without looking it up happens to be the right one to
use for this question !

             Distance  =  (1/2) x (gravity) x (time)²

                   3.8 m  =  (1/2) x (9.8 m/s²) x (time)²

Divide each side
by 4.9 m/s² :

                   (3.8 m) / (4.9 m/sec²)  =  (time)²

                     0.7755  sec²  =  time²

Square root
of each side:

                       0.88 second  =  time
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How does the observed pitch of the buzzer change as it moves
andriy [413]

The answer is

Pitch of the buzzer increased (higher tone) as it moves towards the observer

5 0
2 years ago
PLEASE HELP LOTTA POINTS
sergiy2304 [10]

There's a nasty wrinkle here that's kind of sneaky, and makes the work harder than it should be.

Look at the first question.  There's a number there that's dropped in so quietly that you're almost sure to miss it, but it changes the whole landscape of both of these problems.   That's where it says

" ... 20 cm mark (30 cm from the fulcrum) ... " .

That tells us that the yellow bar resting on the pivot is actually a meter stick, but the pictures don't show the centimeter marks on the stick.  The left end of the stick is "0 cm", the right end of the stick is "100 cm", and the pivot is under the "50 cm" mark.  

When the question talks about hanging a weight, it tells the <em>centimeter mark on the stick</em> where the weight is tied.  To solve the problem, we have to first figure out <em>how far that is from the pivot</em>, then calculate how far from the pivot to put the weight on the other side, and finally <u><em>what centimeter mark that is</em></u> on the stick.      

How to solve the problems:

-- The "moment" of a weight is (the weight) x (its distance from the pivot) .

-- To balance the stick, (the sum of the moments on one side) = (the sum of the moments on the other side).

= = = = = = = = = =  

#1).  Only one moment on the left side.  

(160 gm) x (30 cm from pivot) = 4,800 gm-cm

To balance, we need 4,800 gm-cm of moment on the right side.

(500 gm) x (distance from pivot) = 4,800 gm-cm

Distance from pivot = (4,800 gm-cm) / (500 gm)  =  9.6 cm

The 500 gm has to hang 9.6 cm to the right of the pivot.  But that's not the answer to the problem.  They want to know what mark on the stick to hang it from.  The pivot is at the 50cm mark.  The 500gm has to hang 9.6 cm to the right of the pivot.  That's the <em>59.6 cm</em> mark on the stick.

= = = = =

#2).  There are 2 weights hanging from the left side. We have to find the moment of each weight, add them up, then create the same amount of moment on the right side.

one weight:  120gm, hanging from the 25cm mark.

That's 25cm from the pivot.  Moment = (120gm) (25cm) = 3,000 gm-cm

the other weight:  20gm, hanging from the 10cm mark;

That's 40cm from the pivot.  Moment = (20gm) (40cm) = 800 gm-cm

Add up the moments on the left side:

(3,000 gm-cm) + (800 gm-cm) = 3,800 gm-cm.

To balance, we need 3,800 gm-cm of moment on the right side.

(500 gm) x (its distance from the pivot) = 3,800 gm-cm

Distance from the pivot = (3,800 gm-cm) / (500 gm) = 7.6 cm

The pivot is at the 50cm mark on the stick.  You have to hang the 500gm from 7.6cm to the right of that.  The mark at that spot on the stick is                (50cm + 7.6cm) = <em>57.6 cm </em>.

3 0
3 years ago
Read 2 more answers
The method of creating the illusion of depth on a 2-d surface through the appearance of converging parallel lines and one or mor
user100 [1]
This method is known as linear perspective.
When using linear perspective, artists use a set of drawn or imaginary lines which are made to converge at the horizon of the image. These lines change the viewer's perspective by providing a point through which the relative size, shape and position of objects is determined. This technique creates the illusion of depth.
7 0
3 years ago
An objects weighs 30n on earth a second object weighs 30n on thee moon which has the greatest mass of is it the same
bulgar [2K]
Mass is indirectly proportional to gravity, as moon has less gravity mass would be greater there, if weight of the object is same!

In short, your answer would be "Moon"

Hope this helps!
6 0
3 years ago
Derive velocity-time relation from velocity-time graph ​
Brrunno [24]

Explanation:

hope this helps you

.....,.......

7 0
3 years ago
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