СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃
<h3>Further explanation</h3>
Alkenes are unsaturated hydrocarbons that have a -C = C- double bond.
If there are 2 double bonds it is called an alkadiene, and if there are three double bonds it is called an alkatriene
General formula for Alkenes: CnH2n
addition reactions to alkenes follow Markovnikov's rule. in the addition reaction of hydrogen halide (HX), the halogen atom (X) will be bonded to the carbon atom that binds less H atom.
If the double-bonded carbon atom has the same number of H atoms attached to it, then the X atom will tend to be attached to the carbon atom with the longer alkyl group.
Addition reaction of propene compounds with HCl
СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃
CH - this carbon atom binds fewer H atoms, so Cl is bonded to this bond
Answer:
(a)
(b)
Explanation:
Hello,
In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:
Thus, since the final pressure is 3.60 bar, we can write:
The moles of helium could be computed via solver as:
Or algebraically:
In such a way, the volume of the compartment B is:
Finally, he mole fraction of He is:
Regards.
Reduction Reaction:
Ag⁺ + 1e⁻ → Ag ------ (1)
Oxidation Reaction:
NO₂⁻ → NO₃⁻ + 2e⁻
Balance Oxygen atoms, by adding H₂O to side having less number of O atoms, and H⁺ to side having greater number of O atoms.
NO₂⁻ + H₂O → NO₃⁻ + H⁺ + 2e⁻
Balance the H⁺'s,
NO₂⁻ + H₂O → NO₃⁻ + 2 H⁺ + 2e⁻ ------ (2)
Multiply eq. 1 by 2 to balance the number of electrons in overall reaction.
2 Ag⁺ + 2e⁻ → 2 Ag ----- (3)
Compare eq. 2 and 3,
NO₂⁻ + H₂O → NO₃⁻ + 2 H⁺ + 2e⁻
2 Ag⁺ + 2e⁻ → 2 Ag
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NO₂⁻ + H₂O + 2 Ag⁺ → NO₃⁻ + 2 Ag + 2 H⁺
A spectrum of the electromagnetic radiation emitted by a source.
LiClO3 has mole of mass of 90 g/mol
So 38.7 g means 0.43 mol
Since in this reaction, LiClO3 : O2 = 2:3, then it will produce 0.43*3/2 = 0.645 mol O2
So it is equivalent to 0.645 * 32 = 20.64 g O2