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evablogger [386]
3 years ago
12

You're investigating a subway accident in which a train derailed while rounding an unbanked curve of radius 150 m, and you're as

ked to estimate whether the train exceeded the 35-km/h speed limit for this curve. you interview a passenger who had been standing and holding onto a strap; she noticed that an unused strap was hanging at about a 15 â angle to the vertical just before the accident.

Physics
1 answer:
Ad libitum [116K]3 years ago
8 0
Refer to the diagram shown below.

v =  35 km/h, the speed limit of the train
r = 150 m, the radius of the curve
ω =  angular velocity
m = the mass of the strap
θ° = 15, the angle the strap makes with the vertical
T = tension in the strap

Note that
v = 35 km/h = 35*0.2778 m/s = 9.7223 m/s

The tangential velocity is v = rω, therefore the angular vcelocity is
ω = (9.7223 m/s)/(150 m) = 0.0648 rad/s

The centripetal force tending to make the train derail causes the strap to make an angle of 15 with the vertical.

Let θ =  the maximum allowable angle at  35 km/h.
For horizontal equilibrium,
Tsin(θ) = mrω²
For vertical equilibrium,
Tcos(θ) = mg
Therefore
tan(θ) = (rω²)/g
          = [(150 m)*(0.0648 rad/s)]/(9.8 m/s²)
          = 0.0643
θ = tan⁻¹ 0.0643 = 3.7°

Because 15 > 3.7, we conclude that the train exceeded the 35 km/h speed limit when rounding the curve.

Answer: The train exceeded the 35 km/h speed limit.

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sesenic [268]
1).  Sequence from the Sun:

       Inner planets:
                 Mercury
                 Venus
                 Earth
                 Mars

       Outer planets:
                 Jupiter
                 Saturn
                 Uranus
                 Neptune
            
2).  The farther a planet is from the sun, the longer it takes
to orbit the sun.  Mercury ... 88 days.  Earth ... 365 days.
                           Jupiter ... 12 years.    Neptune ... 165 years.

3).  Mercury & Venus ... no moons
      Earth - 1
      Mars - 2
     Jupiter -  more than 65

4).  Mercury ... cratered, no atmosphere
      Venus ... cratered, thick cloudy atmosphere
       Mars ... dry, cratered, slight atmosphere, like 1% or Earth's
      
       Jupiter, Saturn, Uranus, Neptune
                     We can't see any surface.  If any of them even
                     HAS a surface, it's thousands of miles under a
                     thick atmosphere of methane gas.

5).  Missing from the list

6).  Here's a list from the biggest planet to the smallest one.
The numbers in parentheses are the radius of the planet --
half of the diameter:

Jupiter (69,911 km / 43,441 miles) – 1,120% the size of Earth
Saturn (58,232 km / 36,184 miles) – 945% the size of Earth
Uranus (25,362 km / 15,759 miles) – 400% the size of Earth
Neptune (24,622 km / 15,299 miles) – 388% the size of Earth
Earth (6,371 km / 3,959 miles)
Venus (6,052 km / 3,761 miles) – 95% the size of Earth
Mars (3,390 km / 2,460 miles) – 53% the size of Earth
Mercury (2,440 km / 1,516 miles) – 38% the size of Earth

7). At least seven of the planets rotate in the same direction. 
There's something different about one of them ... it may be Uranus
but I'm not sure.  You'll have to look this up.

8).  Saturn has the famous rings, that you can almost see
with only binoculars.
Spacecraft sent to observe the outer planets have detected
very thin rings around Uranus and Neptune.

9).  Included in #6.

10).  I don't have complete info.  Generally, the closer the planet
is to the sun, the hotter it is.  But there are a few exceptions. 
I think Venus ... the second one from the sun, is actually hotter
than Mercury. 

11).  Just about every language has its own name for each planet.

12).  "Terrestrial" means "like Earth" ("Terra").
The terrestrial planets are the ones that have solid surfaces
and are made of rock.
Mercury, Venus, Earth, and Mars.

13).  "Jovian" means "like Jupiter".
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Jupiter, Saturn, Uranus, Neptune.


4 0
3 years ago
The wavelength of a light wave will affect the light’s
Tom [10]
Frequency and color.
6 0
3 years ago
A 1 pound bucket rests on a table. What is the support force exerted on the bucket by the table? What is the support force when
katrin2010 [14]

This question involves the concepts of equilibrium and Newton's third law of motion.

The support force will be "1 pound" for the empty bucket and the support force will be "6 pounds" after pouring water into it.

  • According to the condition of equilibrium, the sum of forces acting on a stationary object must be zero. Hence, the support force of the table will be equal to the total mass of the bucket.
  • According to Newton's Third Law of Motion every action force has an equal but opposite reaction force. Hence, the support force will be a reaction force to the weight of the bucket.

Therefore, the support force in each case will be equal to the total mass of the bucket:

Case 1 (empty bucket):

<u>support force = 1 pound</u>

<u></u>

Case 1 (water poured):

support force = 1 pound + 5 pound

<u>support force = 6 pound</u>

<u></u>

Learn more about equilibrium here:

brainly.com/question/9076091

8 0
3 years ago
Say that you are in a large room at temperature TC = 300 K. Someone gives you a pot of hot soup at a temperature of TH = 340 K.
DiKsa [7]

Answer:0.061

Explanation:

Given

T_C=300 k

Temperature of soup T_H=340 K

heat capacity of soup c_v=33 J/K

Here Temperature of soup is constantly decreasing

suppose T is the temperature of soup at any  instant

efficiency is given by

\eta =\frac{dW}{Q}=1-\frac{T_C}{T}

dW=Q(1-\frac{T_C}{T})

dW=c_v(1-\frac{T_C}{T})dT

integrating From T_H to T_C

\int dW=\int_{T_C}^{T_H}c_v(1-\frac{T_C}{T})dT

W=\int_{T_C}^{T_H}33\cdot (1-\frac{300}{T})dT

W=c_v\left [ T-T_C\ln T\right ]_{T_H}^{T_C}

W=c_v\left [ \left ( T_C-T_H\right )-T_C\left ( \ln \frac{T_C}{T_H}\right )\right ]

Now heat lost by soup is given by

Q=c_v(T_C-T_H)

Fraction of the total heat that is lost by the soup can be turned is given by

=\frac{W}{Q}

=\frac{c_v\left [ \left ( T_C-T_H\right )-T_C\left ( \ln \frac{T_C}{T_H}\right )\right ]}{c_v(T_C-T_H)}

=\frac{T_C-T_H-T_C\ln (\frac{T_C}{T_H})}{T_C-T_H}

=\frac{300-340-300\ln (\frac{300}{340})}{300-340}

=\frac{-40+37.548}{-40}

=0.061

4 0
3 years ago
A mother and her 35.0 -kg child are riding an escalator to the third level of a shopping mall. If the child's gravitational pote
notka56 [123]

The increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

<h3>What is gravitational potential energy?</h3>

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

The potential energy increases by 3773 J

PE₂-PE₁=mg(h₂-h₁)

3773 J = 35.0 × 9.81 × (h₂-h₁)

(h₂-h₁) = 10.98

Case 2 ;

ΔPE =?

ΔPE=mg(h₂-h₁)

ΔPE=56.0 × 9.81 ×10.98

ΔPE=6031.97 J.

Hence, the increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

To learn more about the gravitational potential energy, refer;

brainly.com/question/3884855#SPJ1

#SPJ1

8 0
2 years ago
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