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Scorpion4ik [409]
3 years ago
14

A 20.0 % by mass solution of phosphoric acid (H3PO4) in water has a density of 1.114 g/mL at 20°C. What is the molarity of this

solution?
Chemistry
2 answers:
saveliy_v [14]3 years ago
5 0

Answer:

Molarity is 2.272M

Explanation:

The mass % of phosphoric acid is 20.0%

It means in 100 g of solution there is 20g of phosphoric acid in it.

Molarity = moles of solute dissolved per litre of solution.

So we need volume of solution

Volume can be calculated from mass and density as

Volume = mass / Density = 100/1.114 = 89.77 mL = 0.08977 L

Moles of solute = mass of solute / molar mass of solute

moles of solute = 20g / 98 = 0.204

molarity = \frac{moles}{volume}=\frac{0.204}{0.08977} =2.272M

bogdanovich [222]3 years ago
3 0
Assume you have 1 L of the material (you can assume any volume you want, you'll get the same answer). 

<span>Using the density, the one L has a mass of 1114 g </span>

<span>20% by mass of phosphoric acid means the mass of phosphoric acid is 0.20 * 1114 g </span>

<span>Calculate the moles of phosphoric acid </span>

<span>Molarity, M, mole / L = moles of acid / volume or 1 L</span>
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Natural gas (CH4) has a molar mass of 16.0 g/mole. You started out the day with a tank containing 200.0 g of natural gas. At the
hodyreva [135]

Considering the definition of molar mass, the moles of gas used are 10.625 moles.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Amount of moles used</h3>

Natural gas has a molar mass of 16.0 g/mole.

You started out the day with a tank containing 200.0 g of natural gas.  So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 200 grams are contained in how many moles?

amount of moles at the beginning=\frac{200 gramsx1 mole}{16 grams}

<u><em>amount of moles at the beginning= 12.5 moles</em></u>

At the end of the day, your tank contains 30.0 g of natural gas. So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 30 grams are contained in how many moles?

amount of moles at the end=\frac{30 gramsx1 mole}{16 grams}

<u><em>amount of moles at the end= 1.875 moles</em></u>

The number of moles used will be the difference between the number of moles used initially and the contents at the end of the day.

moles used= amount of moles at the beginning - amount of moles at the end

moles used= 12.5 moles - 1.875 moles

<u><em>moles used= 10.625 moles</em></u>

<u><em /></u>

Finally, the moles of gas used are 10.625 moles.

Learn more about molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

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3 0
2 years ago
A 2.0 L container of nitrogen gas had a pressure of 3.2 atm. What volume would be necessary to decrease the pressure to 1.0 atm
beks73 [17]

Answer:

6.4 L

Explanation:

When all other variables are held constant, you can use Boyle's Law to find the missing volume:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.

P₁ = 3.2 atm                      P₂ = 1.0 atm

V₁ = 2.0 L                          V₂ = ? L

P₁V₁ = P₂V₂                                                    <----- Boyle's Law

(3.2 atm)(2.0 L) = (1.0 atm)V₂                        <----- Insert values

6.4 = (1.0 atm)V₂                                           <----- Simplify left side

6.4 = V₂                                                        <----- Divide both sides by 1.0

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2 years ago
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B) SO₃(g) + H₂O(l) → H₂SO₄(aq)
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