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aev [14]
4 years ago
12

Help help help help help

Physics
1 answer:
mina [271]4 years ago
7 0
Please mark me brainliest

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A book is being pushed to the right across a desk with a constant acceleration.
nexus9112 [7]

Explanation:

The force would be net positive.

7 0
3 years ago
What standard of measurement do most countries use and discuss why such a standard is beneficial
frosja888 [35]

I mean i guess its the metric system?

6 0
3 years ago
Explain why a 5eV photon of light cannot be absorbed or emitted by the hydrogen atom
sweet [91]

Answer:

None of the transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.

Explanation:

Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy. If it is in the second energy level, it must have -3.4 eV of energy and so on.

If the electron wants to jump from the first energy level, n = 1, to the second energy level n = 2. The second energy level has higher energy than the first, so to move from n = 1 to n = 2, the electron needs to gain energy. It needs to gain (-3.4) - (-13.6) = 10.2 eV of energy to be excited to the second energy level.

The step from the second energy level to the third is much smaller. It takes only 1.89 eV of energy for this excitation to take place. It takes even less energy to excite electrons in hydrogen from the third energy level to the fourth, and even less from the fourth to the fifth.

None of these transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.

5 0
3 years ago
An auto race takes place on a circular track. A car completes one lap in a time of 18.0 s, with an average tangential speed of 4
eduard

Answer:

(A) 0.3488 rad/sec

(B) 124.246 m                

Explanation:

We have given car completes one revolution in 18 sec'

So time period T= 18 sec

Tangential speed v = 43.4 m/sec

(A) Angular velocity is given by \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{18}=0.3488rad/sec

(B) Tangential velocity is given v = 43.4 m /sec

We know that v=\omega r

r=\frac{v}{\omega }=\frac{43.4}{0.3488}=124.426m

4 0
3 years ago
What is the displacement of the object from 12 seconds to 16 seconds
spayn [35]

Answer:

<em>The displacement of the object is -8 m</em>

Explanation:

<u>Displacement</u>

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m

The displacement of the object is -8 m

8 0
3 years ago
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