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tatuchka [14]
3 years ago
6

Johanna is studying what happens to the energy as a ball rolls down a ramp. What is she studying? Check all that apply. gravitat

ional potential energy electrical energy kinetic energy mechanical energy elastic potential energy
Physics
2 answers:
Neko [114]3 years ago
8 0

Answer:

  • gravitational potential energy
  • kinetic energy
  • mechanical energy

Explanation:

Energy possessed by body due to virtue of position is gravitational potential energy and due to motion is known as kinetic energy.

The sum of potential energy and kinetic energy is the mechanical energy. Energy can convert from one form to another but it cannot be created or destroyed.

When ball is at the top of the ramp, it possesses gravitational potential energy which converts to kinetic energy as it rolls down the ramp. The sum of kinetic energy and potential energy i.e. mechanical energy is always constant. Thus she must be studying about these three energies.

vredina [299]3 years ago
3 0
Kinetic energy


because the ball rolling
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Explanation:

The particle will be at rest when its velocity v(t) is equal to zero. Recall that the velocity is simply the derivative of the position x(t) with respect to time:

v(t) = \dfrac{dx}{dt}

Since x(t) = t^2 - 2t + 2

then

v(t) = \dfrac{d}{dt}(t^2 - 2t + 2) = 2t - 2 = 0

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6 0
2 years ago
Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each mo
postnew [5]

Answer:

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

Explanation:

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?

from the principle of momentum

In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.

Take note that momentum is the product of mass and velocity

momentum before collision=momentum after collision

mass, m

u=initial velocity of the identical masses

v2=the common velocity after the collision

Note that the collision is inelastic , since they both moved with the same velocity

umcosφ+umcosφ=(m+m)v2cos−θ2

2mucosφ=2mv2cos−θ2

ucosφ=-v2cosθ2\\\\φ=cos^{-1} (\frac{-v2cosθ2}{cosφ} )

8 0
3 years ago
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