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nordsb [41]
2 years ago
7

What is the average speed of a car that travels 600 km in 10 hours?

Physics
1 answer:
Lady bird [3.3K]2 years ago
6 0

   Average speed = (distance covered) / (time to cover the distance)

                               = (600 km / 10 hr) = 60 km/hr

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A trombone has a variable length. When a musician blows into the mouthpiece and causes air in the tube of the horn to vibrate, t
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Answer:

The frequency increases.

Explanation:

When the Musician draws the slide in the length of the horn gets shorter, which causes a decrease in the wavelength. A decrease in the wave length results in an increase in frequency.

Note:

The diameter of the horn has an effect on frequency, so a wider horn is effectively a long horn - open end correction ( distance between the the antinode and the open end of a pipe).

Frequency also depends on how hard the musician blows the trombone. The musician can change the frequency with the lip pressure being applied.

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Which qualifications are typical for a Manufacturing career? Check all that apply.
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D should be the answer
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Birds fly south for the winter.bats hibernate during winter.what are these examples of
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If a person weighs 818 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that
alexandr402 [8]

Answer:

g'=63.74\ m/s^2

Explanation:

It is given that,

Weight of the person on Earth, W = 818 N

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m=\dfrac{W}{g}

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The mass of an object is same everywhere. It does not depend on the location.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,

g'=\dfrac{W'}{m}

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g'=63.74\ m/s^2

So, the acceleration due to gravity on that planet is 63.74\ m/s^2. Hence, this is the required solution.                                                                    

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Gravitational force is given by, F= G\frac{mM}{R^{2}}

Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.

Gravitational force of the star on planet 1, F_{1}= G\frac{m_{1}M}{R^{2}}

Gravitational force of the star on planet 2, F_{2}= G\frac{3m_{1}M}{(3R)^{2}}

Ratio, \frac{F_{1}}{F_{2}}= \frac{\frac{Gm_{1}M}{R^{2}}}{\frac{G3m_{1}M}{(3R)^{2}}}

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2 years ago
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