A 0.2 kg conductor of length 0.8 m carries 2 ampere current to the right in a magnetic field. What is the magnitude and the dire

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A 0.2 kg conductor of length 0.8 m carries 2 ampere current to the right in a magnetic field. What is the magnitude and the dire

ction of the magnetic field acting on the conductor if the net force on the rod is zero? (Assume that the rod is hung by two insulating supports.)

Physics

2 answers:

Alecsey [184] · Answer 1 · 2022-02-10T02:01:42+03:00

The magnitude and the direction of the magnetic field acting on the conductor if the net force on the rod is zero is 1.225 T and upward force.

<h3>Further explanation </h3>

A 0.2 kg conductor of length 0.8 m carries 2 ampere current to the right in a magnetic field. What is the magnitude and the direction of the magnetic field acting on the conductor if the net force on the rod is zero? (Assume that the rod is hung by two insulating supports.)

$M = 0.2 kg$

$L = 0.8 m$

$g = 9.8$

$I = 2 A$

if there is no net force, the magnetic force BIL equals the weight, M g.

Therefore

$B = \frac{M g}{I L}$

$B = \frac{0.2*9.8}{2.0*0.8} = 1.225 T$

By use the right hand rule, the direction of the B field must produce an upward force.

In physics, the right-hand rule is a common mnemonic for understanding orientation of axes in 3-dimensional space. Most of the various left- and right-hand rules arise from fact that three axes of 3-dimensional space have two possible orientations

<h3>Learn more</h3>

Learn more about conductor brainly.com/question/2182726
Learn more about the magnetic field brainly.com/question/9431418
Learn more about the net force brainly.com/question/2327705

<h3>Answer details</h3>

Grade: 9

Subject: physics

Chapter: the magnetic field

Keywords: conductor, the magnetic field, the net force, insulating, current

miv72 [106K] · Answer 2 · 2022-02-10T00:25:19+03:00

Answer:

The magnetic field is 1.23 T in upward.

Explanation:

Given that,

Mass = 0.2

Length = 0.8 m

Current = 2 A

We need to calculate the magnetic field

If the net force on the rod is zero so the magnetic field is equal to the weight.

Using formula of magnetic force

$mg = BIL$

$B=\dfrac{mg}{IL}$

Put the value into the formula

$B=\dfrac{0.2\times9.8}{2\times0.8}$

$B=1.23\ T$

For direction, using right hand rule

In right hand rule, Thumb represents the force, forefinger represents the magnetic field and the middle finger represents the current.

So,

The direction of the magnetic field is upward.

Hence, The magnetic field is 1.23 T in upward.