Answer:
5.35 rad/s
Explanation:
From the question, we are toldthat an Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick.
Solving this question, the potential energy of the particles must equal to the Kinectic energy i.e
P.E=K.E
Mgh= m½Iω²-------------eqn(*)
Where M= mass of the particles
g= acceleration due to gravity= 9.81m/s^2
ω= angular speed =?
h= height of the particles in the stick on the metre stick= ( 50cm + 80cm)= (0.5m + 0.8m)= 130cm=1.3m
If we substitute the values into eqn(*) we have
m×9.81× (1.3m)= 1/2× m×[ (0.5m)² + [(0.8m)²]× ω²
m(12.74m²/s²)= 1/2× m× (0.25+0.64)× ω
m(12.74m²/s²)= 1/2× m× 0.89× ω²
We can cancel out "m"
12.74= 1/2×0.89 × ω²
12.74×2= 0.89ω²
25.48= 0.89ω²
ω²= 28.629
ω= √28.629
ω=5.35 rad/s
Hence, the angular speed of the meter stick as it swings through its lowest position is 5.35 rad/s
To write it in the form ai + bj, we need to find a and b
which are:
a = x component
b = y component
length of x = 9 – 2 = 7
length of y = 25 – 1 = 24
tan θ = 24 / 7
θ = 73.74°
a = (50 m/s) cos 73.74
a = 14 m/s
b = (50 m/s) sin 73.74
b = 48 m/s
Hence,
14i + 48j
Hi there!
Recall the equation for momentum:
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
We can calculate each object's momentum and compare.
Cement truck:
Race car:
<u>Since 100,000 > 90,000, the cement truck has the greater momentum.</u>
Answer:
2.5 m/s^2
Explanation:
the formula for acceleration (or the one you use in this case) is a=vf-vi/t
where vf is equal to final velocity, vi is equal to initial velocity, and t is equal to time.
vf= 25 m/s
vi= 0m/s
t=10s 25-0=25, 25/10=2.5 therefore it is 2.5m/s^2
