Identify the units NOT used when finding the density?<br><br> 1. Length<br> 2. Volume<br> 3. Mass

In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10

olchik [2.2K]

I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
$\epsilon = -N \frac{\Delta \Phi}{\Delta t}$
where
N is the number of turns in the coil
$\Delta \Phi$ is the variation of magnetic flux through the coil
$\Delta t$ is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
$\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb$
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
$\Phi_f = 0$

Therefore, we can calculate now the induced emf by using the first formula:
$\epsilon = -N \frac{\Delta \Phi}{\Delta t}=- (250) \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V$

7 0

4 years ago

How much work must be done to raise a 1100kg car 2m above the ground?

Xelga [282]

Answer:

21560 J

Explanation:

Work = mg*h = 1100*9.8*2 = 21560 J

4 0

3 years ago

Read 2 more answers

Vector A has magnitude of 8units and makes an angle of 45° with the positive x-axis. Vector B also has the same magnitude of 8un

iragen [17]

Answer:

Explanation:

Because vectors have direction and x and y components you can't just add them and say that their length is 16 because A is 8 units and so is B. What you're actually finding is the magnitude and direction of the vector that results from this addition. The magnitude is the length of the resultant vector, which comes from the x and y components of A and B, and the direction is the angle between the resultant vector and the positive x axis. To add the vectors, then, we need to find the x and y components of each. We'll do the x components of A and B first so we can add them to get the x component of C. Since x values are directly related to cos, the formula to find the x components of vectors is

$V_x=Vcos\theta$ which is the magnitude of the vector (its length) and the angle. Finding the x components of A:

$A_x=8.0cos45$ so

$A_x=5.7$ and for B:

$B_x=8.0cos180$ since the negative x axis is the 180 degree axis and

$B_x=-8.0$ If we add them, we get

$C_x=-2.3$

Now onto the y components. The formula for that is almost the same as the x components except use sin instead of cos:

$A_y=8.0sin45$ so

$A_y=5.7$ and

$B_y=8.0sin180$ so

$B_y=0$ If we add them, we get

$C_y=5.7$

Now for the final magnitude:

$C_{mag}=\sqrt{(-2.3)^2+(5.7)^2}$ and

$C_{mag}=6.1 units$ and now onto the direction.

The x component of C is positive and the y component is negative, which means that the direction has us at an angle is quadrant 2; we add 180 to whatever the angle is. Finding the angle:

$tan^{-1}(\frac{C_y}{C_x})=(\frac{5.7}{-2.3})$ = -68 + 180 = 112 degrees

The resultant vector of A + B has a magnitude of 6.1 and a direction of 112°

Do the same thing for subtraction, except if you're subtracting B from A, the direction that B is pointing has to go the opposite way. That means that A doesn't change anything at all, but B is now pointing towards 0.

$A_x=5.7$ (doesn't change from above)

$B_x=8.0cos0$ and

$B_x=8.0$ so

$C_x=13.7$ and

$A_y=5.7$ (also doesn't change from above)

$B_y=8.0sin0$ so

$B_y=0$ and

$C_y=5.7$ and for the magnitude:

$C_{mag}=\sqrt{(13.7)^2+(5.7)^2$ so

$C_{mag}=15units$ and for the direction:

$tan^{-1}(\frac{5.7}{13.7})=23$ and since both x and y components of C are in Q1, we add nothing.

And you're done!!!

3 0

3 years ago

The power dissipated in a resistor can be written as __________.

Simora [160]

Answer:

$P=I^2R$

Explanation:

The power dissipated in a resistor is given by the equation:

$P=I^2 R$

where

P is the power

I is the current

R is the resistance

We can also rewrite the equation by using Ohm's law:

$V=IR$

where V is the potential difference across the resistor. Rewriting R as

$R=\frac{V}{I}$

The equation for the power becomes

$P=VI$

3 0

3 years ago

The power of lens is measured as reciprocal of focal length.Why?

Leni [432]

Power of a lens is measured by f/D ratio where f is the focal length and D is the diameter of the lens (or mirror). The ratio gives you the power of an optical device or the light gathering power. Please remember a lens focuses the light. Imagine it as a light funnel. A lens works similar to a funnel. It bends the light rays and bring them to a concentrated spot or the focus, just like a funnel that gathers a liquid and bring it out through a narrow spout. Bigger the diameter of the funnel more liquid it can handle. Same way larger diameter of the lens more light it can bring to focal point. That is how you get f/D ratio.
I hope this makes it somewhat clear?

4 0

3 years ago

Identify the units NOT used when finding the density? 1. Length 2. Volume 3. Mass