Answer:
The resistivity of the wire is 
Explanation:
We have,
Length of a wire is 40 cm or 0.4 m
Diameter of a wire is 0.60 mm
Radius is 0.3 mm or 0.0003 m
Resistance of a wire is 1.5 ohm
Now we need to find the resistivity of the material of which it is made. The resistance of a wire in terms of its resistance, length and area is given by :
= resistivity
So, the resistivity of the wire is .
Answer:
the runner's average kinetic energy during the run is 476.96 J.
Explanation:
Given;
mass of the runner, m = 85 kg
distance covered by the runner, d = 42.2 km = 42,200 m
time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)
= 12,600 s
The speed of the runner, v = d/t
v = 42,200 / 12,600
v = 3.35 m/s
The runner's average kinetic energy during the run is calculated as;
K.E = ¹/₂mv²
K.E = ¹/₂ × 85 × (3.35)²
K.E = 476.96 J
Therefore, the runner's average kinetic energy during the run is 476.96 J.
Answer:
Buoyancy force and surface tension are the reactions that take places between soap and pepper experiment.
Explanation:
Surface tension:
The surface tension of a liquid is the tendency of liquid surfaces to resist an external force due to the cohesive nature of its molecules.
The pepper and soap experiment helps you to understand buoyancy force and surface tension.
Reaction between the pepper and soap is as following.
- The pepper flakes float because of buoyancy force. It makes the pepper flakes to move away to the edge of the plate.
- This happens because the liquid dish soap changes the surface tension of water.
- And The pepper flakes are so light, it floats on the water surface due to surface tension.
- when we add soap, it breaks the surface tension of water, but the water resists it. So they pull away from the soap along with the pepper flakes.
- This pushes the pepper away from your soap covered finger.
This is the reaction that take places between soap and pepper experiment.
Learn more about Pepper and soap experiment here:
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Answer:
potential energy is the ability to do work
Answer:
vₓ = 0.566 m / s, W_total = 9.1 J
Explanation:
This exercise is a parabolic type movement, for the x axis where there is no acceleration
x = v t
vₓ = x / t
vₓ = 0.34 / 0.6
vₓ = 0.566 m / s
the work done is
X axis
In this axis there is no acceleration, therefore the sum of the forces is zero and since the work is the force times the distance, we conclude that the lock in this axis is zero.
W₁ = 0
Y axis
in this axis the force that exists is the force of gravity, that is, the weight of the body
W₂ = Fy y
W₂ = mg and
W₂ = m 9.8 0.70
W₂ = m 9.1
the work is a scalar for which we have to add the quantities obtained
W_total = W₁ + W₂
W_total = 0 + 9.1 m
W_total = 9.1 m
In order to complete the calculation, the mass of the body is needed if we assume that the mass is m = 1
W_total = 9.1 J
