initial acceleration of rocket is given as
a = 12 m/s^2
h = 26 m
now we can use kinematics to find its speed



now after this it will be under free fall
so now again using kinematics

at maximum height



total height from the ground = 31.8 + 26 = 57.8 m
Part b)
now after reaching highest height it will fall to ground
So in order to find the speed we can use kinematics again



Part c)
first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s
now we have



after this it will reach to highest point and final speed becomes zero



now from this it will fall back to ground and reach to final speed 33.67 m/s
now we have



so total time is given as
<em>t = 3.44 + 2.55 + 2.1 = 8.1 s</em>
Answer:
i think its false i hope u get it correct
Answer:
-414.96 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration


The force the ground exerts on the parachutist is -414.96 N
If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase
A) F = gravitational force
b) G = universal gravitational constant (6.67 × 10-11 N-m2/kg2)
c) m1 = mass of the body 1
d) m2 = mass of body 2
e) r = radius or distance between the two bodies.
Hope this helps!
Answer:
The magnification is
Explanation:
From the question we are told that
The radius is 
The focal length eyepiece is 
Generally the objective focal length is mathematically represented as

=> 
=> 
The magnification is mathematically represented as

=> 
=> 