A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is
1 answer:
Answer:
<em>The period of the motion will still be equal to T.</em>
<em></em>
Explanation:
for a system with mass = M
attached to a massless spring.
If the system is set in motion with an amplitude (distance from equilibrium position) A
and has period T
The equation for the period T is given as
where k is the spring constant
If the amplitude is doubled, the distance from equilibrium position to the displacement is doubled.
Increasing the amplitude also increases the restoring force. An increase in the restoring force means the mass is now accelerated to cover more distance in the same period, so the restoring force cancels the effect of the increase in amplitude. Hence, <em>increasing the amplitude has no effect on the period of the mass and spring system.</em>
You might be interested in
Answer:
<em>The bullet was 0.52 seconds in the air.</em>
Explanation:
<u>Horizontal Motion </u>
It occurs when an object is thrown horizontally with a speed v from a height h.
The object describes a curved path ruled exclusively by gravity until it hits the ground.
To calculate the time the object takes to hit the ground, we use the following equation:
Note it doesn't depend on the initial velocity but on the height.
The bullet is fired horizontally at h=1.3 m, thus:
t = 0.52 s
The bullet was 0.52 seconds in the air.
Answer:
H = 54.37
Explanation:
given,
lead ball attached at = 1.70 m
rate of revolution = 3 revolution/sec
height above the ground = 2 m
circumference of the circle = 2 π r
= 2 x π x 1.7
= 10.68 m
v = 32.04 m/s
using conservation of energy
H = 54.37
the maximum height reached by the ball is equal to H = 54.37