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nadya68 [22]
4 years ago
11

If an airplane with a mass of 5 tons has gravitational potential energy of 1000 kilojoules, what is its height?

Physics
1 answer:
VLD [36.1K]4 years ago
3 0
The gravitational potential energy of an object, measured with respect to the ground, is given by
U=mgh
where m is the object's mass, g is the gravitational acceleration and h is the height of the object measured from the ground.

In our problem, the mass of the plane is m= 5 tons = 5000 kg, while the potential energy is
U=1000 kJ=1 \cdot 10^6 J
so we can re-arrange the previous formula and use these data to calculate h, the height of the airplane:
h= \frac{U}{mg}= \frac{1 \cdot 10^6 J}{(5000 kg)(9.81 m/s^2)} =20.39 m
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About ________ percent of wais scores fall between 70 and 130.
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The air pressure inside a car tire is
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Answer:

0.137m²

Explanation:

Pressure = Force/Area

Given

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since 1atm = 101325.00 N/m²

3atm = 3(101325.00)

3atm = 303,975N/m²

Pressure = 303,975N/m²

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Area = Force/Pressure

Area = 41500/303,975

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The rate at which energy is transferred is called
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6 0
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A gas always spreads out to fill all available space.<br> True or False <br> Science Hw
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A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic
Fed [463]

Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

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Relative speed of stick v= 0.96 c

Speed of light c= 2.99793\times10^{8}\ m/s

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}

Put the value into the formula

\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}

\Delta l=1\sqrt{1-(0.96)^2}

\Delta l=0.28\ m

We need to calculate the time the stick take to move

Using formula of time

t=\dfrac{\Delta l}{v}

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t=9.72\times10^{-10}\ sec

t=0.97\ ns

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0
3 years ago
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