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Marta_Voda [28]
3 years ago
9

What do the arrows in food chains represent

Physics
2 answers:
OLga [1]3 years ago
6 0
To represent in order how the animals

Andre45 [30]3 years ago
6 0
To represent what eats what
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If a melon has a a mass of 1 kg, how much does the melon weigh?
My name is Ann [436]

Explanation:

1kg = approximately 10N

6 0
2 years ago
What force does it take to accelerate a 7.2 kg object 3.0 m/s^2.
grin007 [14]

Answer:

<h2>21.6 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7.2 × 3 = 21.6

We have the final answer as

<h3>21.6 N</h3>

Hope this helps you

3 0
2 years ago
How many different types of atoms are present in one molecule of aluminum hydroxide, Al(OH)3?
tatyana61 [14]
There are approximately 3 different types of atoms that are present in one molecule of aluminum hydroxide, AI(OH)3.
8 0
3 years ago
Read 2 more answers
Water enters a typical garden hose of diameter 0.016 m with a velocity of 3 m/s. Calculate the exit velocity of water from the g
Vladimir79 [104]

Answer:

v₂ = 306.12 m/s

Explanation:

We know that the volume flow rate of the water or any in-compressible liquid remains constant throughout motion. Therefore, from continuity equation, we know that:

A₁v₁ = A₂v₂

where,

A₁ = Area of entrance pipe = πd₁²/4 = π(0.016 m)²/4 = 0.0002 m²

v₁ = entrance velocity = 3 m/s

A₂ = Area of nozzle = πd₂²/4 = π(0.005 m)²/4 = 0.0000196 m²

v₂ = exit velocity = ?

Therefore,

(0.0002 m²)(3 m/s) = (0.0000196 m²)v₂

v₂ = (0.006 m³/s)/(0.0000196 m²)

<u>v₂ = 306.12 m/s</u>

5 0
3 years ago
The ratio of carbon-14 to nitrogen-14 is an artifact is 1:3. Given that half-life of carbon-14 is 5730years, how old is the arti
dusya [7]

Answer:

9155 years old

Explanation:

We use the following expression for the decay of a substance:

N = N_0\,\,e^{-k*t}

So we first estimate the value of k knowing that the half-life of the C14 is 5730 years:

N = N_0\,\,e^{-k*t}\\N_0/2=N_0\,\,e^{-k*5730}\\1/2 = e^{-k*5730}\\ln(1/2)=-k*5730\\k= 0.00012

so, now we can estimate the age of the artifact by solving for"t" in the equation:

1/3=e^{-0.00012*t}\\ln(1/3)= -0.00012*t\\t=9155. 102

which we can round to 9155 years old.

5 0
3 years ago
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