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12345 [234]
3 years ago
5

Use the drop-down menus to complete the statement about Earth’s magnetism.

Physics
2 answers:
Rufina [12.5K]3 years ago
6 0

Answer:

core, iron, churning

Explanation:

Nataly [62]3 years ago
5 0

Answer:

The Earth's magnetism is generated in the core, which is composed of iron that is constantly churning

Explanation:

Magnetic fields are produced by charges in motion, therefore by currents.

The outer core of the Earth consists mainly of melted iron that is in constant motion. This iron in motion actually acts as a giant current, and therefore it is responsible for the creation of the Earth's magnetic field.

The magnetic field of the Earth is very weak, in fact its magnitude is on average between 25 and 65 microtesla (for comparison, normal magnets can even produce magnetic fields of a few millitesla).

However, its role is very important for the Earth: in fact, it provides a shield that blocks most of the harmful radiation coming from the Sun.

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Calculate the electric field at the location of a charge if the electric force is 10 newtons and the charge on the particle is 6
kolezko [41]

I think it may be c, 1.7 v. I work with electricity a lot.


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3 years ago
The two fundamental styles of design established in early motion pictures are the ___________ associated with the lumière brothe
castortr0y [4]

The answer in the first space provided is realistic whereas the second space provided is fantastic. The correct answer would be letter B.

In realistic, it has many views in which the frame is the window on the world whereas fantastic depicts imagination or remotes from reality.

5 0
2 years ago
What is the speed of the block/bullet system after the collision? express your answer in terms of vi, mw, and mb. hints?
Sonbull [250]
Having said that, 
mV + M0 = (m + M)v; where m = bullet mass, M = block mass, V = bullet velocity upon incoming, and v = the block and bullet velocity (ideal without losses) is the answer you are looking for. Thus, v = V(m/(m + M)) is what you want. m = Mb, M = Mw, and V = Vi.
6 0
2 years ago
Temperatures expressed in the Kelvin scale are ____ higher than temperatures in the Celsius scale?
Cerrena [4.2K]
Answer: D. 273


Explanation: Celsius temperatures can be negative while kelvin goes down to absolute zero and doesn’t go any lower, thus no negative numbers
4 0
2 years ago
One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0.70 times the mass of our sun. This planet
Stels [109]

0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.

Answer: Option B

<u>Explanation:</u>

Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

               \frac{G M m}{r^{2}}=m \omega^{2} r

The orbit’s period is given by,

               T=\sqrt{\frac{2 \pi}{\omega r^{2}}}=\sqrt{\frac{r^{3}}{G M}}

Where,

T_{e} = Earth’s period

T_{p} = planet’s period

M_{s} = sun’s mass

r_{e} = earth’s radius

Now,

             T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}

As, planet mass is equal to 0.7 times the sun mass, so

            T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}

Taking the ratios of both equation, we get,

             \frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}

            \frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}

            \left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}

            \left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}

           \frac{r_{e}}{r_{p}}=\left(\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}

Given T_{p}=9.5 \text { days } and T_{e}=365 \text { days }

          \frac{r_{e}}{r_{p}}=\left(\left(\frac{365}{9.5}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=\left(\frac{133225}{90.25} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=(2108.82)^{\frac{1}{3}}

         r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}

7 0
2 years ago
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