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Lena [83]
3 years ago
13

Calculation of Molar Ratios of Conjugate Base to Weak Acid from pH For a weak acid with a pKa of 6.0, calculate the ratio of con

jugate base to acid at a pH of 5.0.
Choice of Weak Acid for a Buffer Which of these com-pounds would be the best buffer at pH 5.0: formic acid (pKa 5 3.8), acetic acid (pKa 5 4.76), or ethylamine (pKa 5 9.0)? Briefly justify your answer.
Chemistry
1 answer:
Free_Kalibri [48]3 years ago
7 0

Explanation:

According to the Handerson equation,  

          pH = pK_{a} + log \frac{\text{salt}}{\text{acid}}

or,      pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

Putting the given values into the above equation as follows.

     pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

       5.0 = 6.0 + log \frac{\text{conjugate base}}{\text{acid}}[/tex]

      log \frac{\text{conjugate base}}{\text{acid}} = -1.0

or,      \frac{\text{conjugate base}}{\text{acid}} = 10^{-1.0}

                            = 0.1

Therefore, we can conclude that molar ratios of conjugate base to weak acid for given solution is 0.1.

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3 years ago
Which element is classified as an alkali metal?
Delvig [45]

Answer: The alkali metals consist of the chemical elements lithium (Li), sodium (Na), potassium (K),[note 1] rubidium (Rb), caesium (Cs),[note 2] and francium (Fr).

Explanation:

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4 years ago
Determine the number of carbon atoms in 1.00 kg of carbon dioxide.
olga2289 [7]

Answer:

1.37x10²⁵atoms of carbon

2.74x10²⁵ atoms of oxygen.

33.7g of KNO₃

Explanation:

To answer this question you must use molar mass of carbon dioxide (44g/mol) and 1 mole are 6.022x10²³atoms.

1.00kg are 1000g of CO₂. Moles are:

1000g CO₂ * (1mol / 44g) = 22.73 moles of CO₂ = 22.73 moles of carbon.

In atoms:

22.73 moles C * (6.022x10²³atoms / 1mole) = 1.37x10²⁵atoms of carbon

There are 22.73 moles of CO₂ * 2 = 45.45 moles of oxygen are present in the carbon dioxide. In atoms:

45.45 moles Oxygen * (6.022x10²³atoms / 1mole) = 2.74x10²⁵ atoms of oxygen.

1 mole of Potassium nitrate, KNO₃, contains 3 moles of oxygen. 1 mol of oxygen are:

1.00 mol O * (1mol KNO₃ / 3 moles O) = 0.33 moles of KNO₃

As molar mass of KNO₃ is 101.1g/mol:

0.33 moles of KNO₃ * (101.1g / mol) = 33.7g of KNO₃

5 0
3 years ago
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a desired trait from one organism is placed into that of another organism with human intervention.

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Calculate the fraction of lattice sites that are Schottky defects for cesium chloride at 623 oC (this temperature is below the m
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Answer:

5.9 × 10^-6.

Explanation:

In the arrangements of crystal solids there is likely going to be an imperfection or defect and one of the defect or imperfections in the arrangements of solids is known as the Schottky defects. The Schottky defects is a kind of lattice arrangements imperfection that occurs when positively charged ions and negatively charged ions leave their position.

So, let us delve right into the solution of the question. We will be making use of the formula below;

Wb/ W = e^ - c/ 2kT.

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Wb/ W= 0.000005896557435956372.

Wb/ W=5.9 × 10^-6.

3 0
3 years ago
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