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Lena [83]
3 years ago
13

Calculation of Molar Ratios of Conjugate Base to Weak Acid from pH For a weak acid with a pKa of 6.0, calculate the ratio of con

jugate base to acid at a pH of 5.0.
Choice of Weak Acid for a Buffer Which of these com-pounds would be the best buffer at pH 5.0: formic acid (pKa 5 3.8), acetic acid (pKa 5 4.76), or ethylamine (pKa 5 9.0)? Briefly justify your answer.
Chemistry
1 answer:
Free_Kalibri [48]3 years ago
7 0

Explanation:

According to the Handerson equation,  

          pH = pK_{a} + log \frac{\text{salt}}{\text{acid}}

or,      pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

Putting the given values into the above equation as follows.

     pH = pK_{a} + log \frac{\text{conjugate base}}{\text{acid}}

       5.0 = 6.0 + log \frac{\text{conjugate base}}{\text{acid}}[/tex]

      log \frac{\text{conjugate base}}{\text{acid}} = -1.0

or,      \frac{\text{conjugate base}}{\text{acid}} = 10^{-1.0}

                            = 0.1

Therefore, we can conclude that molar ratios of conjugate base to weak acid for given solution is 0.1.

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Calculate the molarity of a KCl solution if 37.3 g of KCl are dissolved in water to give a
saw5 [17]

Answer:

1M

Explanation:

find concentration in g/cm^3,then molar mass of kcl(39+35.5),if 1mol=74.5g what about 74.6

8 0
3 years ago
Two billiard balls having masses of 0.2 kg and 0.15kg approach each other. The first ball having a velocity of 2m/s hit the seco
Gekata [30.6K]

Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

Explanation:

Given: m_{1} = 0.2 kg,      m_{2} = 0.15 kg

v_{1} = 2 m/s,    v_{2} = 0 m/s,      v'_{1} = ?,          v'_{2} = 1.5 m/s

Formula used is as follows.

m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}

where,

v = velocity before collision

v' = velocity after collision

Substitute the values into above formula as follows.

m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}\\0.2 kg \times 2 m/s + 0.15 kg \times 0 m/s = 0.2 kg \times v'_{1} + 0.15 kg \times 1.5 m/s\\0.4 kg m/s + 0 = 0.2v'_{1} + 0.225 kg m/s\\0.2v'_{1} kg = 0.175 kg m/s\\v'_{1} = \frac{0.175 kg m/s}{0.2 kg}\\= 0.875 m/s

Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

4 0
3 years ago
The three end stages of stars are Red Giant Phase, Second Red Giant Phase and White Dwarf Phase correct?
solong [7]

Answer: Most of the stars in the universe are main sequence stars — those converting hydrogen into helium via nuclear fusion. A main sequence star may have a mass between a third to eight times that of the sun and eventually burn through the hydrogen in its core. Over its life, the outward pressure of fusion has balanced against the inward pressure of gravity. Once the fusion stops, gravity takes the lead and compresses the star smaller and tighter.

Temperatures increase with the contraction, eventually reaching levels where helium is able to fuse into carbon. Depending on the mass of the star, the helium burning might be gradual or might begin with an explosive flash.

6 0
3 years ago
Suppose that the mechanism of hydrolysis of tert- butyl chloride preceded by a different mechanism so that the predicted rate la
ddd [48]

Answer:

B, because that was the answer on quizlet.

Explanation:

5 0
3 years ago
Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04
evablogger [386]

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

8 0
3 years ago
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