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galben [10]
3 years ago
10

You test a machine and find that it exerts a force of 5 N for each 2 N of force you exert operating the machine. What is the act

ual mechanical advantage of the machine?
Physics
1 answer:
maw [93]3 years ago
6 0

Answer:

The actual mechanical advantage is the mechanical advantage determined by physical measurement of the input and output forces.

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t is the estimated distance traveled through the air by a marshmallow that is launched from a 15- cm long launcher when it is pl
DerKrebs [107]

Answer:

10

Explanation:

15 cm minus 5 cm

5 0
3 years ago
I need help with this answer
7nadin3 [17]

Answer:

double replacement

Explanation:

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8 0
3 years ago
A mass of 3.6 kg oscillate on a horizontal spring with a spring constant of 160 N/m.
Darya [45]

Answer:

48.7 J

Explanation:

For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.

In particular:

- The elastic potential energy is maximum when the system is at its maximum displacement

- The kinetic energy is maximum when the system passes through the equilibrium position

Therefore, the maximum kinetic energy of the system is given by:

KE=\frac{1}{2}mv^2

where

m is the mass

v is the speed at equilibrium position

In this problem:

m = 3.6 kg

v = 5.2 m/s

Therefore, the maximum kinetic energy is:

KE=\frac{1}{2}(3.6)(5.2)^2=48.7 J

6 0
3 years ago
A 6.00-kg box sits on a ramp that is inclined at 37.0° above the horizontal. the coefficient of kinetic friction between the box
forsale [732]
We need to see what forces act on the box:

In the x direction:

Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.

In the y direction:

N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 

From N-Gcosα=0 we get: 

N=Gcosα, we will need this for the force of friction.

Now to solve for Fh:

Fh=ma + Ff + Gsinα,

Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²

Fh=ma + μmgcosα+mgsinα

Now we plug in the numbers and get:

Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N

The horizontal force for pulling the body up the ramp needs to be Fh=71 N.
8 0
3 years ago
Frictional force is caused by the interaction of a body with​
zheka24 [161]

Answer:

Frictional force always acts parallel to two planes in contact with each other and in a direction opposite to that of relative motion of the two bodies. 2. Frictional forces are caused due to intermolecular interactions between the bodies.  Frictional force is more for rough surface and less for smooth surfaces.

6 0
3 years ago
Read 2 more answers
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