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Svetllana [295]
3 years ago
8

The compressibility factor provides a quick way to assess when the ideal gas law is valid. Use a solver to find the minimum temp

erature where the fluid has a vapor phase compressibility factor greater than 0.95 at 3 MPa. Report the value in oC, without units.
Engineering
1 answer:
marishachu [46]3 years ago
8 0

Answer:

The answer is

Explanation:

The compressibility factor

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In a right triangle, the square of the length of one side is equal to the sum of the squares of the lengths of the other two sid
Dovator [93]

Answer:

C++ code is explained below

Explanation:

/Remove the following line

//if not using visual studio.

#include "stdafx.h"

//Import the required header files.

#include <iostream>

using namespace std;

//Define the main function.

int main(void)

{

    //Define the variables.

    double side1, side2, side3;

    //Prompt the user to enter the sides of the triangle.

    cout << "Enter the side of the triangle:" << endl;

    cout << "Enter first side of triangle:" << endl;

    cin >> side1;

    cout << "Enter second side of triangle:" << endl;

    cin >> side2;

    cout << "Enter third side of triangle:" << endl;

    cin >> side3;

    cout << endl;

    //Check if the triangle sides are valid

    if ((side1 + side2 > side3) &&

         (side1 + side3 > side2) &&

         (side2 + side3 > side1))

    {

         //Check the condition for right angle triangle

         if ((side3*side3 == (side1*side1 + side2*side2)) ||

             (side2*side2 == (side3*side3 + side1*side1)) ||

             (side1*side1 == (side3*side3 + side2*side2)))

//Display that the triangle is right-angled triangle.

             cout << "It is a right-angled triangle." << endl;

         else

//Display that the triangle is not the right-//angled triangle.

             cout << "It is not a right-angled triangle."

<< endl;

    }

    else

         //Display not the valid side.

         cout << "Not a valid side." << endl;

    //Remove the following line if

    //not using visual studio.

    system("pause");

    return 0;

}

8 0
3 years ago
Describe the role of C-S-H in providing strength for cement. Discuss which compounds produce C-S-H and why balancing the amounts
wariber [46]

Answer:

Following are the solution to this question:

Explanation:

Whenever a chemical reaction occurs between water and cement the heat is released, and a CaOSiO_2H_2O (C-S-H gel) gel constructs gel is also recognized as "tobermorite gel."

This one gel acts like a pack of gum and also has a cement quality, that holds its particles intact and therefore contributes to the overall compression mix. An increase in supply explicitly causes the movement in the outcome of power. C3S and C2S are both the compounds of Bouge that produce hydration C-S-H gel.

It mixture must be balanced as Ca(OH)_2 with C-S-H gel also is given as a byproduct. It Ca(OH)_2 , that cause sudden with sulphate and form CaSO_4 , is an unacceptable substance. Sulfate attack or later deterioration of its cement is caused by this CaSO_4 .

All C3S and C2S generate various amounts of C-S-H gel so, the required strength can be maintained without compromising on real term durability.

8 0
3 years ago
Thermal energy measured by?
Harlamova29_29 [7]

Answer:

Thermal energy is measured using a thermometer denominated in Fahrenheit, Celsius and Kelvin

3 0
2 years ago
If the bolt head and the supporting bracket are made of the same material having a failure shear stress of 'Tra;i = 120 MPa, det
Nina [5.8K]

Answer:

P=361.91 KN

Explanation:

given data:

brackets and head of the screw are made of material with T_fail=120 Mpa

safety factor is F.S=2.5

maximum value of force P=??

<em>solution:</em>

to find the shear stress

                            T_allow=T_fail/F.S

                                         =120 Mpa/2.5

                                         =48 Mpa

we know that,

                               V=P

<u>Area for shear head:</u>

                              A(head)=π×d×t

                                           =π×0.04×0.075

                                           =0.003×πm^2

<u>Area for plate:</u>

                               A(plate)=π×d×t  

                                            =π×0.08×0.03

                                            =0.0024×πm^2

now we have to find shear stress for both head and plate

<u>For head:</u>

                                   T_allow=V/A(head)

                                    48 Mpa=P/0.003×π                 ..(V=P)

                                             P =48 Mpa×0.003×π

                                                =452.16 KN

<u>For plate:</u>

                                   T_allow=V/A(plate)

                                    48 Mpa=P/0.0024×π                 ..(V=P)

                                             P =48 Mpa×0.0024×π

                                                =361.91 KN

the boundary load is obtained as the minimum value of force P for all three cases. so the solution is

                                                P=361.91 KN

note:

find the attached pic

7 0
3 years ago
Drag each item to show if it is an element or not an element.
Flauer [41]

Answer:

CARBON

Explanation:

HOPE THIS HELPS SORRY FOR CAPS

5 0
3 years ago
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