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omeli [17]
2 years ago
7

I

Physics
1 answer:
valentinak56 [21]2 years ago
7 0

Answer:

mass is 56.25 N

Explanation:

F=ma

325=4m

m=325/4

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What change occurs to the mass of an object when an unbalanced force is applied to it
strojnjashka [21]
The mass of an object always stays the same since it is really just the amount of matter in an object so no matter the force applied, as long as the object does not lose or gain matter, the object stays the same
5 0
1 year ago
T-Joe (65 kg) is running at 3 m/s. T-Brud (50 kg) is running at 4 m/s. What would be T-Joe's momentum?
Debora [2.8K]

Answer:

P_J=195N

Explanation:

From the question we are told that

Mass\ of T-joe\ M_J=65\\Velocity\ of T-joe\ V_J=3m/s\\Mass of\ T-Brud\ M_B=50kg\\Velocity\ of T-Brud\ V_B=3m/s\\

Generally the equation for momentum is mathematically given by

P=mv

Therefore

T-Joe momentum P_J

P_J=65*3

P_J=195N

5 0
2 years ago
What are most elements on the periodic table?
Molodets [167]

Answer:

Metals, nonmetals and metalloids.

Explanation:

5 0
3 years ago
Read 2 more answers
Two parallel wires separated by 4.00cm repel each other with a force per unit length of 2.00×10⁻⁴ N/m . The current in one wire
oksian1 [2.3K]

The force will be doubled if direction of one current is reversed and doubled.

The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.

With a distance of 4.00 cm between them, two parallel wires repel one another with a force of 2.00 × 10⁻⁴ N/m. One wire is carrying 5.00 A of current.

I₁ = 5 A

d = 4 cm

F = 2 × 10⁻⁴ N/m

We have, F/L = μ₀ I₁ I₂ / L

Now, we know the force is directly proportional to the product of the current, and the direction of one current is reversed and doubled.

The force of interaction would become attractive and its magnitude would double as a result of switching the directions of either of the currents and doubling their size.

Learn more about force here:

brainly.com/question/12970081

#SPJ4

7 0
1 year ago
A 7.00 g bullet, when fired from a gun into a 1.10 kg block of wood held in a vise, penetrates the block to a depth of 9.60 cm.
kvasek [131]

Explanation:

The given data is as follows.

    Mass of bullet 1, m_{b} = 7 g = 7 \times 10^{-3} kg

   Mass of block of wood, M = 1.10 kg

   Bullet penetrates to depth, x_{1} = 9.60 cm = 9.60 \times 10^{-2} m

  Mass of bullet 2, m_{B} = 7 g = 7 \times 10^{-3} kg

  Velocity of bullet = v

Let us assume that depth of penetration of the bullet is x_{2}.

According to the law of conservation of energy,

            Kinetic energy = Potential energy

        Kinetic energy = \frac{1}{2}mv^{2}

and,       Potential energy = mgh

so, for bullet 1

           \frac{1}{2}m_{b}v^{2}_{1} = m_{b}gx_{1} .......... (1)

For bullet 2,

     Kinetic energy of bullet 1 - kinetic energy of bullet 2 = Potential energy

 \frac{1}{2}m_{b}v^{2}_{1} - \frac{1}{2}(M + m_{b} + m_{B})v^{2}_{2} = m_{b}gx_{2}

Using equation (1), we get

      m_{b}gx_{1} - \frac{1}{2}(M + m_{b} + m_{B})v^{2}_{2} = m_{b}gx_{2}

        x_{2} = \frac{x_{1}(M + m_{b})}{(M + m_{b} + m_{B})}

Putting the given values into the above formula as follows.

        x_{2} = \frac{x_{1}(M + m_{b})}{(M + m_{b} + m_{B})}

                   = \frac{9.60 \times 10^{-2}(1.10 + 7 \times 10^{-3})}{(1.10 + 7 \times 10^{-3} + 7 \times 10^{-3})}

                   = 0.0953 m

or,                = 9.53 cm    (as 1 m = 100 cm)

Thus, we can conclude that the bullet will penetrate at a depth of 9.53 cm.

5 0
3 years ago
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