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Scrat [10]
3 years ago
8

If we assume that 60 % of the kinetic energy delivered by a 1.80-kg hammer with a speed of 7.80 m/s is transformed into heat tha

t flows into the nail and does not flow out, what is the temperature increase of an 8.00-g aluminum nail after it is struck ten times?
Physics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

45.6°C

Explanation:

Kinetic energy = \frac{1}{2}mv^2

Use m= 1.80kg and v=7.80m/s (mass and speed of hammer).

K = 0,5*1.80kg*(7.80m/s)^2 = K=54.8J

Heat is 60% of Kinetic energy. Q = 0.6*54.8J = 32.9J

As it is stuck 10 times the total heat is 10*32.9J = Total Heat = 329J

Use the equation Q = mC_v \Delta T to find change of temperature:

\Delta T = \frac{Q}{mC_v}

Q = 329J; m = 8.00g of aluminium; C_v = 0.900J/g°C (For aluminium)

\Delta T = \frac{329J}{8.00g*0.900J/g°C}

Calculating gives Change of Temperature = 45.6°C

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