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Elina [12.6K]
3 years ago
9

Fundamental differences in the cell, the basic unit of life, allow for broadest classification of all living organisms into thre

e domains: Bacteria,Achaea and Eukarya. which of the following can organisms NOT classified on?
A. Ability to obtain nutrients
B. Mode of reproduction
C. Physical characteristics
D. Lacking a nucleus
Chemistry
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

C

Explanation:

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What are the best topics to write a project work on EVS and Chemistry​
professor190 [17]

Answer:

It is better to do chemistry

Explanation:

So that you will learn more of chemicals

6 0
2 years ago
Use the Lab Report document as a template. Use the descriptions and examples of each part to help you write your Lab Report. You
GarryVolchara [31]
This link might help you!!

https://www.eiu.edu/biology/bio1500/writing_a_lab_report.pdf
6 0
2 years ago
if it takes 54 ml of 0.100 M naoh to neutralize 125ml of an hcl solution, what is the concentration of the hcl
vichka [17]

Answer:

c = 0.0432moldm ^−3

Explanation:

The first step would be to find the molar ratio in the reaction. Now generally, one can simplify strong acid-strong base reaction by saying:

Acid+Base ->Salt+ Water

4 0
2 years ago
For the reaction
azamat

Answer:

Mass = 5.56 g

Explanation:

Given data:

Mass of Cl₂ = 4.45 g

Mass of NaCl produced = ?

Solution:

Chemical equation:

2Cl₂ + 4NaOH     →   3NaCl + NaClO₂ + 2H₂O

Number of moles of Cl₂:

Number of moles = mass/molar mass

Number of moles = 4.45 g/ 71 g/mol

Number of moles = 0.063 mol

Now we will compare the moles of Cl₂ with NaCl.

                  Cl₂         :         NaCl

                    2          :          3

                 0.063      :        3/2×0.063 =0.095 mol

Mass of NaCl:

Mass = number of moles × molar mass

Mass = 0.095 mol × 58.5 g/mol

Mass = 5.56 g

7 0
2 years ago
Calculate the molality of a solution prepared by dissolving 175 g of KNO3 in 750 g of water. (round to nearest hundreth)
Wittaler [7]
We will get the molality from this formula:
Molality = no.of moles of solute / Kg of solvent 

So first we need the no.of moles of KNO3 = the mass of KNO3 / molar mass of KNO3
no.of moles of KNO3 = 175 / 101.01 = 1.73 mol
By substitution in the molality formula:
∴ molality = 1.73 / (750/1000) = 2.3 Molal

6 0
3 years ago
Read 2 more answers
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