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vaieri [72.5K]
3 years ago
11

A cart rolling down an incline for 5.0 seconds has an acceleration of 4.0 m/sec2. If the cart has a beginning 

Physics
1 answer:
Zolol [24]3 years ago
6 0
S = V1 + a* t
S = 2 + 4 * 5
V2 SQR =V1SQR + 2as
V2SQR = 2*2 + 2*4*22 =180
V2 =SQRT180
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Need help to get this question right!!
Charra [1.4K]

Answer:

16 times as strong

Explanation:

From the question given above, the following assumptions were made:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

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Next, we shall obtain a relationship between the force and the distance apart. This can be obtained as follow:

F = GM₁M₂ / r²

Cross multiply

Fr² = GM₁M₂

If G, M₁ and M₂ are kept constant, then,

F₁r₁² = F₂r₂²

Finally, we determine the new force as follow:

Initial Force (F₁) = F

Initial distance apart (r₁) = r

Final distance apart (r₂) = ¼r

Final force (F₂) =?

Fr² = F₂ × (¼r)²

Fr² = F₂ × r²/16

Fr² = F₂r² / 16

Cross multiply

16Fr² = F₂r²

Divide both side by r²

F₂ = 16Fr² / r²

F₂ = 16F

From the calculations made above, we can see that the new force is 16 times the original force.

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