Answer:
5080.86m
Explanation:
We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:
We must consider that it's launched from the ground (
) and from rest (
), with an upwards acceleration 
that lasts a time t=9.7s.
We calculate then the height achieved in part 1:
And the velocity achieved in part 1:
We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (
) and its initial velocity is the one achieved in part 1 (
), now in free fall, which means with a downwards acceleration 
. For the data we have it's faster to use the formula 
, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:
Then, to get 
, we do:
And we substitute the values:
I think it is c density and temperature
Answer:
option D
Explanation:
given,
A conductor is carrying current = 2.0 A is 0.5 mm thick
Hall voltage = 4.5 x 10-6 V
uniform magnetic field = 1.2 T
density of the charge = n =?
hall voltage =
n = 6.67 × 10²⁷ charges/m
hence the correct answer is option D
Answer:
420 L
Explanation:
Applying Boyle's Law,
PV = P'V'.................... Equation 1
Where P = Initial pressure, P' = Final pressure, V = Initial volume, V' = Final volume.
make V' the subject of the equation
V' = PV/P'.................... Equation 2
From the question,
Given: P = 720 mmHg, V = 350 L, P' = 600 mmHg
Substitute these values into equation 2
V' = (720×350)/600
V' = 252000/600
V' = 420 L
Explanation:
S =ut + 1/2at^2
S = 0×6.5 + (1/2 × 9.54) × 6.5^2
S =0 + 4.77 ×42.25
S=201.5m
