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dem82 [27]
3 years ago
5

What is the difference between “exercise” and “physical activity”?

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0
Physical activity is movement that is carried out by the skeletal muscles that requires energy. In other words, any movement one does is actually physical activity. Exercise, however, is planned, structured, repetitive and intentional movement intended to improve or maintain physical fitness.
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Which of the following is not a synthesis reaction?
Nastasia [14]
C is the awnser because c is single replacement
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3 years ago
Why do astronomers use the word on to describe angles on the sky rather than angles in the sky?
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<span>The use of the word on instead of the word in when referring to the angular distance between celestial objects comes about because all of the objects appear to be on the celestial sphere and at an indeterminable distance. While we know that objects are at different distances in the sky, their distance from Earth is irrelevant in determining the angular distance between the two objects as viewed from Earth.</span>
8 0
3 years ago
A cannon is fired straight up into the air. If the cannon ball comes back down to the launch point in 5 seconds, what was the ma
Nana76 [90]

Answer:

30.63 m

Explanation:

From the question given above, the following data were obtained:

Total time (T) spent by the ball in air = 5 s

Maximum height (h) =.?

Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:

Total time (T) spent by the ball in air = 5 s

Time (t) taken to reach the maximum height =.?

T = 2t

5 = 2t

Divide both side by 2

t = 5/2

t = 2.5 s

Thus, the time (t) taken to reach the maximum height is 2.5 s

Finally, we shall determine the maximum height reached by the ball as follow:

Time (t) taken to reach the maximum height = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

h = ½gt²

h = ½ × 9.8 × 2.5²

h = 4.9 × 6.25

h = 30.625 ≈ 30.63 m

Therefore, the maximum height reached by the cannon ball is 30.63 m

3 0
3 years ago
An engineer wishes to design a curved exit ramp for a toll road in such a way that a car will not have to rely on friction to ro
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T_y = ncosA = mg

Dividing both.

tan A = \frac{v^2}{rg}

tan A = \frac{11.7^2}{50*9.8}

A = tan^{-1} (0.279367)

A = 15.608\°

Therefore the angle that should the curve be banked is 15.608°

7 0
3 years ago
Fa car's power output is increased, its efficiency:
Inessa [10]
It’s solved by using a pretty standard formula for efficiency.

4 0
3 years ago
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